Answer:
The slope of the graph is what you need. That tells you the speed not the velocity. In order to find the velocity you would also need to know the direction of the motion.
The linear speed of the pepperoni is 0.628 m/s. Its direction is tangential to the circle.
We know that;
v = rω
r = radius of the piece = 10 cm or 0.1 m
ω = angular velocity
We have to convert 60 revolutions per minute to radians per second
1 rev/min = 0.10472 rad/s
60 revolutions per minute = 60 rev/min × 0.10472 rad/s/1 rev/min
= 6.28 rad/s
v = 0.1 m × 6.28 rad/s
v = 0.628 m/s
The direction of this velocity is tangential to the circle.
Learn more: brainly.com/question/4612545
Answer:
28 degree C
Explanation:
We are given that




We have to find the temperature on a spring day when resistance is 215.1 ohm.
We know that

Using the formula




Hence, the temperature on a spring day 28 degree C.
<span>The choices can be found elsewhere and as follows:
</span><span>a. they are so small that they stay close to the ground due to the attractive properties of charged soil particles.
b. they are easily carried by the wind.
c. they easily dissolve in liquid droplets.
d. it is easier for then to roll along the small crevices in the ground.</span><span>
</span>I think the correct answer from the choices listed above is option B. Only the smallest particles of soil can be displaced by suspension because they are so small that they are easily carried by the wind. Hope this answers the question. Have a nice day. Feel free to ask more questions.
Answer:
The magnitude of the magnetic field halfway between the wires is 3.0 x 10⁻⁵ T.
Explanation:
Given;
distance half way between the parallel wires, r = ¹/₂ (40 cm) = 20 cm = 0.2 m
current carried in opposite direction, I₁ and I₂ = 10 A and 20 A respectively
The magnitude of the magnetic field halfway between the wires can be calculated as;

where;
B is magnitude of the magnetic field halfway between the wires
I₁ is current in the first wire
I₂ is current the second wire
μ₀ is permeability of free space
r is distance half way between the wires

Therefore, the magnitude of the magnetic field halfway between the wires is 3.0 x 10⁻⁵ T.