A 38.0 kg child is in a swing that is attached to ropes 1.70 m long. The acceleration of gravity is 9.81 m/s 2 . Find the gravit
1 answer:
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Answer:
(a)
Average velocity = < 0, 316000, 146000> m/s
(b) < 0, 2.844, 1.314 > m
Explanation:
r1 = < 0.02, 0.04, - 0.06 > m
r2 = < 0.02, 1.62, - 0.79 > m
time, t = 5 micro second = 5 x 10^-6 s
(a) Average velocity is defined as the ratio of total displacement to the total time taken.
Displacement = r = r2 - r1
r = < 0.02 - 0.02, 1.62 - 0.04, - 0.79 + 0.06 > m
r = < 0, 1.58, - 0.73 > m
So. Average velocity =
Average velocity =
Average velocity = < 0, 316000, 146000> m/s
(b)
Distance = velocity x time
Here time, t = 9 micro second
d = < 0, 316000, 146000> x 9 x 10^-6 m
d = < 0, 2.844, 1.314 > m
The maximum speed is 10.4 m/s
Explanation:
For a body in uniform circular motion, the centripetal acceleration is given by:
where
v is the linear speed
r is the radius of the circular path
In this problem, we have the following data:
- The maximum centripetal acceleration must be
where is the acceleration of gravity. Substituting,
- The radius of the turn is
r = 10 m
Therefore, we can re-arrange the equation to solve for v, to find the maximum speed the ride can go at:
Learn more about centripetal acceleration:
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