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vlada-n [284]
3 years ago
5

Calculate the number of moles of carbon dioxide produced with a gas volume of a 115 mL at a temperature of 21゚C and water vapor

corrected pressure of 746 mm HG?
Chemistry
1 answer:
UkoKoshka [18]3 years ago
3 0

Answer:

n = 0.005 mol

Explanation:

Given data:

Volume = 115 mL

Temperature = 21°C

Pressure = 746 mmHg

Number of moles = ?

Solution:

746 mmHg = 746 /760 = 0.98 atm

21°C = 21+273 = 294 K

115 mL /1000 = 0.115 L

PV = nRT

n = PV/RT

n = 0.98 atm ×  0.115 L / 0.0821 atm. L. mol⁻¹. K⁻¹ ×294 K

n = 0.1127 atm. L /24.14 atm. L. mol⁻¹

n = 0.005 mol

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A rectangular block has the following dimensions: 3.21 dm, 5.83 cm, and 1.84 in. The block has a mass of 1.94 kg. What is the de
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The density of the rectangular block in g/mL is 7.0.

<u>Given the following data:</u>

  • Mass of block = 22.8 gra1.94 kg
  • Length of block = 3.21 cm
  • Width of block = 5.83 cm
  • Height of block = 1.84 in.

To find the density of the block in g/mL:

First of all, we would determine the volume of the rectangular block by using the following formula:

Volume = length × width × height

<u>Conversion:</u>

1 in = 2.54 cm​

5.83 in = X cm

Cross-multiplying, we have:

X = 2.54(5.83)\\\\X = 14.81 \; cm

Volume = 3.21 × 5.83 × 14.81

Volume = 277.16 cubic centimeters.

<u>Note</u>: Milliliter (mL) is the same as cubic centimeters.

1000 grams = 1 kg

Y grams = 1.94 kg

Cross-multiplying, we have:

Y = 1940 grams

Now, we can find the density:

Density = \frac{Mass}{Volume}\\\\Density = \frac{1940}{277.16}

<em>Density </em><em>= 7</em><em>.0 g/mL</em>

Therefore, the density of the rectangular block in g/mL is 7.0.

Read more: brainly.com/question/18320053

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