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VladimirAG [237]
3 years ago
14

The human ear can detect a remarkable range of sound intensities. The quietest sound that we can hear has an intensity of 10−1

2W/m^2, and we begin to feel pain when the intensity reaches 1 W/m^2. Since the intensities that matter to people in everyday life cover a range of 12 orders of magnitude, intensities are usually converted to a logarithmic scale called the sound intensity level β, which is measured in decibels (dB).
Required:
Use this technique to find a formula for the intensity I of a sound, in terms of the sound level beta and the reference intensity Io.
Physics
1 answer:
SIZIF [17.4K]3 years ago
5 0

Answer:

I = Io 10^{β/10}

Explanation:

To find a formula for the intensity of sound waves you use the fact that there is a great range of intensity that human can perceive.

The use of logarithms are useful for this kind of systems. For example, if you want a 10 scale for the measurement of the sound level  you can write:

\beta=10log(\frac{I}{I_o})    (1)

I: intensity of sound

Io: hearing threshold

From the equation (1) you can find I in terms of Io and β. You use properties of the logarithms to obtain:

\beta=log(\frac{I}{I_o})^{10}\\\\10^{\beta}=10^{log(\frac{I}{I_o})^{10}}\\\\10^{\beta}=(\frac{I}{I_o})^{10}\\\\I=(I_o^{10}10^{\beta})^{\frac{1}{10}}=I_o10^{\frac{\beta}{10}}

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An ion with charge of Q = +3.2 x 10-19 C is in a region where a uniform electric field of magnitude E = 5.0 X 105 V/m is perpend
san4es73 [151]

Answer:

option C

Explanation:

given,

Q = +3.2 x 10⁻¹⁹ C

E = 5.0 X 10⁵ V/m

B = 0.80 T

ion's acceleration is zero  

when acceleration is zero the magnitude of both the forces becomes equal.

q E = q V B

v = \dfrac{E}{B}

v= \dfrac{5 \times 10^5}{0.80}

v = 6.25 × 10⁵ m/s ≈ 6.3 × 10⁵ m/s

hence, the correct answer is option C

8 0
3 years ago
Convert 43 km/h to m/s.​
SIZIF [17.4K]

Answer:

43km/h to m/s = 11.9444

Explanation:

1 km = 1000 m; 1 hr = 3600 sec. To convert km/hr into m/sec, multiply the number by 5 and then divide it by 18.

6 0
3 years ago
A rock is launched at angle theta=53.2∘ above the horizontal from an altitude of ℎ=182 km with an initial speed ????0=1.61 km/s.
Mariulka [41]

Answer:

The rock's final speed at the required altitude will be 42.24 m/s.

Explanation:

Let's start by finding the initial vertical speed.

Vertical Speed = 1.61 * Sin (53.2°)

Vertical Speed = 0.8 m/s

We want to know the speed of the rock when it is at an altitude of 91 km.

The total displacement of the rock from its starting position will thus be equal to -91 km

We can use this in the following equation:

s=u*t+\frac{1}{2} (a*t^2)

-91=0.8*t+\frac{1}{2} (-9.8*t^2)

t = 4.3918 seconds

Thus it takes 4.3918 seconds to reach the required altitude. We can now find the speed as follows:

V=U+at

V=0.8+(-9.8)*(4.3918)

V = -42.24

Thus the rock's final speed at the required altitude will be 42.24 m/s.

8 0
4 years ago
Read 2 more answers
If a ball that is 10 meters above the ground is thrown horizontally at 5.51 meters per second. a. how long will it take for the
GalinKa [24]

Answer:

a. t = 1.43 s

b. d = 7.88 m

Explanation:

a. The time of flight can be found using the following equation:

y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}

Where:

y_{f}: is the final height = -10 m

y_{0}: is the initial height = 0

v_{0_{y}}: is the initial speed in the vertical direction = 0

g: is the acceleration due to gravity = 9.81 m/s²

By solving the above equation for "t" we have:

t = \sqrt{\frac{2y_{f}}{g}} = \sqrt{\frac{2*10 m}{9.81 m/s^{2}}} = 1.43 s

Hence, the ball will hit the ground in 1.43 s.

b. The distance in the horizontal direction can be found as follows:

x_{f} = x_{0} + v_{0}t + \frac{1}{2}at^{2}

Where:

x₀: is the initial position in the horizontal direction = 0

a: is the acceleration in the horizontal direction = 0 (it is moving at constant speed)

x_{f} = 5.51 m/s*1.43 s = 7.88 m

Therefore, the ball will travel 7.88 m before it hits the ground.

I hope it helps you!

4 0
3 years ago
The perceived loudness of a sound is measured in
diamong [38]
<h2>Answer: decibels </h2>

The decibel dB is the relation between two values: the pressure produced by a sound wave and a pressure taken as a reference. Resulting in a dimensionless value.

It should be noted that itself<u> is not a unit of measure</u>, since in reality the unit is bel B (which <u>is not part of the International System of Units</u>) in honor of Alexander Graham Bell.

However, given the amplitude of the measured elements in practice, its submultiple, the decibel, is used. That is, this quotient is a logarithmic expression, where 1dB=0.1B

5 0
3 years ago
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