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3 years ago

What does it mean for a weak acid to be in equilibrium

2 answers:

7 0

When an uncharged weak acid is added to water, a homogeneous equilibrium forms in which aqueous acid molecules, HA(aq), react with liquid water to form aqueous hydronium ions and aqueous anions, A-<span>(aq). The latter are produced when the acid molecules lose H+ ions to water.</span>

Paraphin [41]3 years ago

5 0

Weak acid dissociates partially in water to form hydronium ion and conjugate base of the acid. Since the acid is weak the conjugate base is strong. Acetic acid is a weak acid which dissolves in water to form hydronium ion and acetate ions (conjugate base).

CH₃COOH + H₂O → H₃O⁺ + CH₃COO⁻

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Write the balanced equation for the reaction of aqueous sodium carbonate and aqueous calcium chloride dihydrate to form solid ca

faltersainse [42]

5 0

3 years ago

Read 2 more answers

An interplanetary probe returns to Earth with soil samples. The atoms in the sample are sorted by their number of protons. A new

Leya [2.2K]

Answer is: the average atomic mass is 232.

ω₁ = 20% ÷ 100%.

ω₁ = 0.20.

ω₂ = 80% ÷ 100%.

ω₂ = 0.80.

Ar₁ = 120 (number of protons) + 120 (number of neutrons).

Ar₁ = 240.

Ar₂ = 120 + 110 .

Ar₂ = 230.

Average atomic mass of atoms of bolognium =

Ar₁ · ω₁ + Ar₂ · ω₂.

Average atomic mass of atoms of bolognium = 240 · 0.2 + 230 · 0.8.

Average atomic mass of atoms of bolognium = 48 + 184.

Average atomic mass of atoms of bolognium = 232.

4 0

3 years ago

The density of a 3.37M MgCl2 (FW = 95.21) is 1.25 g/mL. Calulate the molality, mass/mass percent, and mass/volume percent. So fa

Dafna1 [17]

Answer : The molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

Solution : Given,

Density of solution = 1.25 g/ml

Molar mass of $MgCl_2$ (solute) = 95.21 g/mole

3.37 M magnesium chloride means that 3.37 gram of magnesium chloride is present in 1 liter of solution.

The volume of solution = 1 L = 1000 ml

Mass of $MgCl_2$ (solute) = 3.37 g

First we have to calculate the mass of solute.

$\text{Mass of }MgCl_2=\text{Moles of }MgCl_2\times \text{Molar mass of }MgCl_2$

$\text{Mass of }MgCl_2=3.37mole\times 95.21g/mole=320.86g$

Now we have to calculate the mass of solution.

$\text{Mass of solution}=\text{Density of solution}\times \text{Volume of solution}=1.25g/ml\times 1000ml=1250g$

Mass of solvent = Mass of solution - Mass of solute = 1250 - 320.86 = 929.14 g

Now we have to calculate the molality of the solution.

$Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{3.37g\times 1000}{95.21g/mole\times 929.14g}=0.0381mole/Kg$

The molality of the solution is, 0.0381 mole/Kg.

Now we have to calculate the mass/mass percent.

$\text{Mass by mass percent}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100=\frac{320.86}{1250}\times 100=25.67\%$

The mass/mass percent is, 25.67 %

Now we have to calculate the mass/volume percent.

$\text{Mass by volume percent}=\frac{\text{Mass of solute}}{\text{Volume of solution}}\times 100=\frac{320.86}{1000}\times 100=32.086\%$

The mass/volume percent is, 32.086 %

Therefore, the molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

8 0

3 years ago

What do atomic-scale models show you that your observations of properties cannot?

Zigmanuir [339]

The atomic number is the number of protons in the nucleus of an atom. The number of protons define the identity of an element.

4 0

3 years ago

If kc = 7.04 × 10-2 for the reaction: 2 hbr(g) ⇌h2(g) + br2(g), what is the value of kc for the reaction: 1/2 h2(g) + 1/2 br2 ⇌h

Kay [80]

At the first reaction when 2HBr(g) ⇄ H2(g) + Br2(g)
So Kc = [H2] [Br2] / [HBr]^2
7.04X10^-2 = [H2][Br] / [HBr]^2

at the second reaction when 1/2 H2(g) + 1/2 Br2 (g) ⇄ HBr
Its Kc value will = [HBr] / [H2]^1/2*[Br2]^1/2
we will make the first formula of Kc upside down:
1/7.04X10^-2 = [HBr]^2/[H2][Br2]
and by taking the square root:
∴ √(1/7.04X10^-2)= [HBr] / [H2]^1/2*[Br]^1/2
∴ Kc for the second reaction = √(1/7.04X10^-2) = 3.769

7 0

4 years ago