Answer:
The major effects of ice accretion on the aircraft is that it disturbs the flow of air and effects the aircraft's performance.
Explanation:
The ice accretion effects the longitudinal stability of an aircraft as:
1. The accumulation of ice on the tail of an aircraft results in the reduction the longitudinal stability and the elevator's efficacy.
2. When the flap is deflected at 
with no power there is an increase in the longitudinal velocity.
3. When the angle of attack is higher close to the stall where separation occurs in the early stages of flow, the effect of ice accretion are of importance.
4. When the situation involves no flap at reduced power setting results in the decrease in aircraft's longitudinal stability an increase in change in coefficient of pitching moment with attack angle.
The EMV - Ending Market Value is given as:
$2,400,000.
<h3>How is the EMV Arrived At?</h3>
The EMV is given as:
BMV x (i + r); Where
BMV is the Beginning Market Value; and
r is the interest rateor percentage given.
Hence the EMV = 2,000,000 x ( 1 + 20%)
= 2,000,000 x 1.2
= $ 2, 400,000.
It is to be noted that the BMV is the Beginning Market Value which is the value of an investment at the start of the business period.
Learn more about Market Value at:
brainly.com/question/1350233
Answer:
How to Test for a Blind Spot . As you have learned, the blind spot is an area on your retina that has no visual receptors. Because of this, there is a tiny gap in your visual field. While your brain usually fills in the missing information so that you don't notice it, this quick and easy test makes it possible to demonstrate the blind spot , Of this, 300 crashes are, sadly, fatal. 2 Accidents are just as likely on Australian roads if blind spots are ignored. Not every car has blind-spot detection, so it's best to educate drivers about the importance of the blind spot to avoid accidents. However, not acknowledging the blind spot when driving isn't just dangerous for other cars on.
Explanation:
Answer:
a) the inductance of the coil is 6 mH
b) the emf generated in the coil is 18 mV
Explanation:
Given the data in the question;
N = 570 turns
diameter of tube d = 8.10 cm = 0.081 m
length of the wire-wrapped portion l = 35.0 cm = 0.35 m
a) the inductance of the coil (in mH)
inductance of solenoid
L = N²μA / l
A = πd²/4
so
L = N²μ(πd²/4) / l
L = N²μ(πd²) / 4l
we know that μ = 4π × 10⁻⁷ TmA⁻¹
we substitute
L = [(570)² × 4π × 10⁻⁷× ( π × (0.081)² )] / 4(0.35)
L = 0.00841549 / 1.4
L = 6 × 10⁻³ H
L = 6 × 10⁻³ × 1000 mH
L = 6 mH
Therefore, the inductance of the coil is 6 mH
b)
Emf ( ∈ ) = L di/dt
given that; di/dt = 3.00 A/sec
{∴ di = 3 - 0 = 3 and dt = 1 sec}
Emf ( ∈ ) = L di/dt
we substitute
⇒ 6 × 10⁻³ ( 3/1 )
= 18 × 10⁻³ V
= 18 × 10⁻³ × 1000
= 18 mV
Therefore, the emf generated in the coil is 18 mV
Explanation:!!
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