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Lapatulllka [165]
3 years ago
5

The east-west row planting orientation is preferred to maximize light absorption of

Engineering
1 answer:
Katyanochek1 [597]3 years ago
8 0

Answer: True

Explanation:

The east-west row planting orientation helps in the maximize the light absorption by plants which then brings about an efficient photosynthesis activity.

Also, it helps in the shading of weeds that can be found in the inter-row space. Also, it brings about an improvement on drop yield crop yield.

Therefore, the answer to the above is true.

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A converging-diverging nozzle has an area ratio of 5.9. (1) Determine the (P0/Pt) values corresponding to the 1st, 2nd, and 3rd
nata0808 [166]

Answer:

Check the explanation

Explanation:

The Total pressure is the overall of fixed or static pressure p, the dynamic pressure q, as well as gravitational head. Total pressure can also be referred to as the measure of the overall energy of the airstream, and is the same to static pressure plus velocity pressure.

kindly check the step by step solution in the attached image below to Determine the (P0/Pt) values corresponding to the 1st, 2nd, and 3rd critical points.

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4 years ago
How much to build a barber clipper?
goldenfox [79]
Like the price to manufacture?
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3 years ago
How many paragraphs are good for an essay
zhannawk [14.2K]

Answer:

It depends what type of essay you're writing. Normally you'll want an intro, three body paragraphs and then a conclusion, but if you're writing an argumentative essay you will want an intro par, three body par, a counterclaim and rebuttal par, and a conclusion par.

Explanation:

Typically 5 or 6 paragraphs will work, really just depends what type of essay.

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3 years ago
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The Molybdenum with an atomic radius 0.1363 nm and atomic weight 95.95 has a BCC unit cell structure. Calculate its theoretical
Nookie1986 [14]

Solution:

Given :

atomic radius, r = 0.1363nm = 0.1363×10⁻⁹m

atomic wieght, M = 95.96

Cell structure is BCC (Body Centred Cubic)

For BCC, we know that no. of atoms per unit cell, z = 2

and atomic radius, r =\frac{a\sqrt{3} }{4}

so, a = \frac{4r}{\sqrt{3}}

m = mass of each atom in a unit cell

mass of an atom = \frac{M}{N_{A} },

where, N_{A} is Avagadro Number = 6.02×10^{23}

volume of unit cell = a^{3}

density, ρ = \frac{mass of unit cell}{volume of unit cell}

density, ρ = \frac{z\times M}{a^{3}\times N_{A}}

ρ = \frac{2\times 95.95}{(\frac{4\times 0.1363\times 10^{-9}}{\sqrt{3}})^{3}\times (6.23\times 10^{23})}

ρ = 10.215gm/cm^{3}

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4 years ago
Question #4
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C. they need on the job experience I think

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