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Ipatiy [6.2K]
3 years ago
5

Which of the following best describes the rock cycle?

Chemistry
2 answers:
DedPeter [7]3 years ago
5 0

Answer:

D. The rock cycle is a series of processes in which one kind of rock is transformed into other kinds.

Explanation:

bekas [8.4K]3 years ago
5 0

Answer:

it is the last one.

<em><u>The </u></em><em><u>rock </u></em><em><u>cycle </u></em><em><u>is </u></em><em><u>a </u></em><em><u>series </u></em><em><u>of </u></em><em><u>processes </u></em><em><u>in </u></em><em><u>which </u></em><em><u>one </u></em><em><u>kind </u></em><em><u>of </u></em><em><u>rock </u></em><em><u>is </u></em><em><u>transformed </u></em><em><u>into </u></em><em><u>other </u></em><em><u>kinds</u></em><em><u>. </u></em>

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Identify the type of bonding within each substance. Co ( s ) ionic covalent metallic CoCl 2 ( s ) covalent ionic metallic CCl 4
krok68 [10]

Answer:

1. Co ( s ) - metallic bonding

2. CoCl₂ ( s ) - ionic bonding

3. CCl₄ ( l ) - covalent bonding

Explanation:

Metallic bonding -

It is the type of bonding present between the atoms of the metals , via the electrostatic interaction between the metal and the delocalized electrons , is known as metallic bonding .

For example ,

Mostly metals show metallic bonding .

Ionic bonding -

It is the type of bonding present between the ions i.e. , the cation and the anion is known as ionic bonding .

For example ,

Mostly ionic compound , like salts show ionic bonding .

Covalent bonding -

It is the type of bonding which is present between shared pair of electrons , is known as covalent bonding .

For example ,

Most of the carbon compounds are capable to show covalent bonding .

Hence , from the question ,

1. Co ( s ) - metallic bonding

2. CoCl₂ ( s ) - ionic bonding

3. CCl₄ ( l ) - covalent bonding  

6 0
3 years ago
2 What is the correct sequence of steps for the preparation of a pure sample of copper(II) sulfate
Lina20 [59]

Answer:

The correct answer is - B. dissolving → evaporation filtration → crystallisation

Explanation:

The method of the preparation of a pure sample of copper(II) sulfate from dilute sulfuric acid and copper II oxide is given as follows:

step 1. Adding dilute sulfuric acid into a beaker. Using bunsen burner heat the beaker.

step 2. Adding the copper (II) oxide into the beaker and give it a little time at a time to the warm dilute sulfuric acid and stir

step 3. Filtering the mixture into an evaporating vessel to remove the excess copper (II) oxide and water from the filtrate.

Step 4. leave the rest filtrate to crystallize.

Copper (II) Oxide  {CuO (s)}  +  Dilute Sulfuric Acid {H2SO4 (aq)}   →  Copper (II) Sulphate {CuSO4 (s)}   +  Water {H2O}

4 0
2 years ago
If there is no subscript to the right of a symbol means ________________ atom of that element?
julia-pushkina [17]

Explanation:

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3 0
3 years ago
Describe two physical and two chemical changes involved in cooking. (4 points)
Ivenika [448]
Physical changes are when things get changed without altering chemical consistencies, which is melting solid butter into liquid one, or boiling water. Chemical changes are things such as caramelizing sugar when making sweets, or when carbon dioxide is created and released when baking bread.
7 0
3 years ago
Gold forms face-centered cubic crystals. The atomic radius of a gold atom is 144 pm. Consider the face of a unit cell with the n
kipiarov [429]

Answer:

The length of an edge of this unit cell is 407.294 pm

Explanation:

Face centered cubic structure contains 4 atoms in each unit cell and 12 coordination number, occupying about 74% volume of the total cell. Face centered cubic structure is known for efficient use of space for atom packing.

To determine the edge length, a relationship between the radius of the atom and edge length is used.

X = R√8

Where;

X is the length of an edge of this unit cell

R is the radius of the gold atom = 144 pm = 144 X 10⁻¹² m

X = 144 X 10⁻¹²√8

X = 407.294 X 10⁻¹² m

X = 407.294 pm

Therefore, the length of an edge of this unit cell is 407.294 pm

8 0
2 years ago
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