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Masteriza [31]
3 years ago
6

How many grams of fluorine are required to produce 10.0 g of XeF6?

Chemistry
1 answer:
mote1985 [20]3 years ago
7 0
Moles XeF6 = 10.0 g/ 245.28 g/mol=0.0408

the ratio between F2 and XeF6 is 3 : 1

moles F2 required = 3 x 0.0408=0.122

mass F2 = 0.122 mol x 37.9968 g/mol=4.64 g
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How many electrons does hydrogen need in order to have a full shell of valence electrons?
eimsori [14]

Answer:

It only needs one electron.

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2 years ago
covalent bond would be formed in which pair of elements? Carbon and oxygen, any two noble gasses, sodium and chlorine , between
SOVA2 [1]

Answer:

Carbon and Oxygen, Argon and Helium.

Explanation:

noble gases have full outer shells of electrons, and so cannot share other atoms' electrons to form bonds. sodium and chlorine form an ionic bond.

4 0
3 years ago
Help people i really need this
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3 years ago
) How many moles are there in 2.00 x 10^19 molecules of calcium phosphate?
Tamiku [17]

Answer:

\huge 3.322 \times  {10}^{ - 5}  \:  \: moles  \\

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{2.00 \times  {10}^{19} }{6.02 \times  {10}^{23} }  \\  \\  = 3.322 \times  {10}^{ - 5}  \:  \: moles

Hope this helps you

4 0
2 years ago
The combustion of hydrogen-oxygen mixtures is used to produce very high temperatures (ca. 2500 °C) needed for certain types of w
tangare [24]

Answer:

1360kJ are evolved

Explanation:

When 1mole of H2 reacts with 1/2 moles O2 producing 1 mole of water and 241.8kJ.

To solve this question we need to find the limiting reactant knowing were added 90g of H2 and 90g of O2 as follows:

<em>Moles H2 -Molar mass: 2g/mol-</em>

90g H2 * (1mol / 2g) = 45 moles

<em>Moles O2 -Molar mass: 32g/mol-</em>

90g * (1mol / 32g) = 2.81moles

For a complete reaction of 2.81 moles of O2 are needed:

2.81 moles O2 * (1mol H2 / 1/2 mol O2) = 5.62 moles H2

As there are 45 moles, H2 is the excess reactant and O2 the limiting reactant.

As 1/2 moles O2 produce 241.8kJ, 2.81 moles will produce:

2.81 moles O2 * (241.8kJ / 1/2moles O2) =

<h3>1360kJ are evolved</h3>
6 0
2 years ago
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