How many grams of fluorine are required to produce 10.0 g of XeF6?

1 answer:

mote1985 [20]3 years ago

7 0

Moles XeF6 = 10.0 g/ 245.28 g/mol=0.0408

the ratio between F2 and XeF6 is 3 : 1

moles F2 required = 3 x 0.0408=0.122

mass F2 = 0.122 mol x 37.9968 g/mol=4.64 g

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