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IrinaK [193]
3 years ago
15

6A certain load and set of slings create a 20-degree angle between the load and each sling leg. Using a spreader for the same li

ft would result in a 60-degree angle between the load and each sling leg. What is the reduction (in percent) in sling stress and in the horizontal reaction when the spreader is used?

Physics
1 answer:
Otrada [13]3 years ago
5 0

Solution:

The angle between the sling and the load is 20^{\circ}

So the  tension in each sling can be calculated as

Sin \theta = Mg => T = \frac{Mg}{2Sin\theta}

Sin \theta=> \frac{Mg}{2Sin 20^{\circ}}

Where    

M is the mass of the load

The Horizontal reaction on the sling will be inward.

After using the spreader, the new angle between sling and load is 60^{\circ}, the tension in the sling will be  

T= \frac{Mg}{2 Sin 60^{\circ}} = \frac{Mg}{2 Sin 20^{\circ}}

The tension will be same as before in the sling move away through the spreader at an angle more than 90 degree the horizontal force will act opposite and will be outward

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A) 50 cm

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Explanation

Step 1

A)

If you know the distance between nodes and antinodes then use this equation:

\begin{gathered} \frac{\lambda}{2}=D \\ \text{where}\lambda\text{ is the wavelength} \\ D\text{ is the distance betw}een\text{ nodes} \end{gathered}

then, let

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now, replace to find the wavelength

\begin{gathered} \frac{\lambda}{2}=25 \\ \text{Multiply both sides by 2} \\ \frac{\lambda}{2}\cdot2=25\cdot2 \\ \lambda=50\text{ Cm} \end{gathered}

so, the wavelength is

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Step 2

The speed of a wave can be found using the equation

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then,let

\begin{gathered} \lambda=50\text{ cm} \\ f=200\text{ Hz} \end{gathered}

replace and evaluate

\begin{gathered} v=\lambda f \\ v=50\text{ cm }\cdot200\text{ HZ} \\ v=10000\text{ }\frac{\text{cm}}{s} \end{gathered}

so

B) 10000 cm/s

I hope this helps you

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