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taurus [48]
3 years ago
11

Sand is poured at a constant rate of 75.5 g/s into a 0.540-kg bucket resting on a scale. If sand is landing in the bucket with a

speed of 3.70 m/s, determine the scale reading when there is 0.550 kg of sand in the bucket.
Physics
1 answer:
worty [1.4K]3 years ago
4 0

Answer:10.961 N

Explanation:

Given

mass flow rate in bucket is \dot{m}=75.5 g/s

mass of bucket m=0.540 kg

velocity of sand v=3.70 m/s

Force acting on bucket due to incoming of sand is given by

F=\frac{\mathrm{d} m}{\mathrm{d} t}v

F=75.5\times 10^{-3}\times 3.7=279.35\times 10^{-3} N

Now weight of sand and bucket when 0.55 kg sand is Present in bucket

W_1=(0.54+0.55)\times 9.8

W_1=1.09\times 9.8=10.68 N

Total reading on scale will be addition of weight and force acting by incoming sand

Reading =10.68+0.279=10.961 N

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If the final speed of an object as is strikes the ground is 77 m/s and it was in the air for 6.5 seconds. What was the initial d
azamat

Answer:

The answer to your question is: 13.2 m/s

Explanation:

final speed (fs) = 77 m/s

t = 6.5 s

gravity (g) = 9.81 m/s2

initial speed (is) = ?

Formula

fs = is + gt     from this equation we clear "is" = fs - gt

Substitution                         is = 77 - (9,81)(6.5)

Process                               is = 77 - 63.8

                                            is = 13.2 m/s

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3 years ago
For a moon orbiting its planet, rp is the shortest distance between the moon and its planet andra is the longest distance betwee
Natasha2012 [34]

Answer: D. 0.57

Explanation:

The formula to calculate the eccentricity e of an ellipse is (assuming the moon's orbit in the shape of an ellipse):

e=\frac{r_{a}-r_{p}}{r_{a}+r_{p}}

Where:

r_{a} is the apoapsis (the longest distance between the moon and its planet)

r_{p}=0.27 r_{a} is the periapsis (the shortest distance between the moon and its planet)

Then:

e=\frac{r_{a}-0.27 r_{a}}{r_{a}+0.27 r_{a}}

e=\frac{0.73 r_{a}}{1.27 r_{a}}

e=0.57 This is the moon's orbital eccentricity

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Can i have the physical science grade 12 june 2021 paper (common paper)​
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Answer:

u have to purchase it via online e-commerce platforms

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How can we use thermal energy to our advantage?
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Answer:

One of the primary advantages of thermal power is that the generation costs are extremely low. No fuel is needed to generate the power, and the minimal energy needed to pump water to the Earth's surface can be taken from the total energy yield.

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The force of attraction between two oppositely charged pith is 5mx 10 to the -6th power newtons. If the charge on the two is 6.7
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Answer:

0.28 m

Explanation:

The following data were obtained from the question:

Force (F) = 5×10¯⁶ N

Charge 1 (q₁) = 6.7×10¯⁹ C

Charge 2 (q₂) = 6.7×10¯⁹ C

Electrical constant (K) = 9×10⁹ Nm²C¯²

Distance apart (r) =?

Thus, the distance between the two charges can be obtained as follow:

F = Kq₁q₂/r²

5×10¯⁶ = 9×10⁹ × 6.7×10¯⁹ × 6.7×10¯⁹/r²

5×10¯⁶ = 4.0401×10¯⁷ / r²

Cross multiply

5×10¯⁶ × r² = 4.0401×10¯⁷

Divide both side by 5×10¯⁶

r² = 4.0401×10¯⁷ / 5×10¯⁶

Take the square root of both side

r = √(4.0401×10¯⁷ / 5×10¯⁶)

r = 0.28 m

Therefore, the distance between the two charges is 0.28 m

4 0
3 years ago
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