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Karo-lina-s [1.5K]

3 years ago

9

Vitamin C has the formula CxHyOz. You burn 0.778 g of the compound in a combustion analysis chamber and isolate 1.17 g of CO2 an

d 0.317 g of H2O. Enter an integer or a decimal number, such as 2 or 1.5 or 1.67. What is the ratio of mol H to mol O in the sample

1 answer:

Komok [63]3 years ago

7 0

Answer: 4 : 3

Explanation:Please see attachment for explanation

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Which reaction results in the GREATEST increase in entropy?

Nitella [24]

I would say D would be the answer

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2 years ago

Given 5.0 grams of lead (II) nitrate and 3.0

natulia [17]

Answer:

1.70 g of NaNO₃

Explanation:

The balance chemical equation for given double displacement reaction is,

Pb(NO₃)₂ + 2 NaI → PbI₂ + 2 NaNO₃

Step 1: <u>Calculate moles of each reactant:</u>

Moles = Mass / M.Mass

For Pb(NO₃)₂:

Moles = 5.0 g / 331.21 g/mol

Moles = 0.0150 moles

For NaI:

Moles = 3.0 g / 149.89 g/mol

Moles = 0.020 moles

Step 2: <u>Calculate Limiting reagent as;</u>

According to equation,

1 mole of Pb(NO₃)₂ reacts with = 2 moles of NaI

So,

0.0150 moles of Pb(NO₃)₂ will react with = X moles of NaI

Solving for X,

X = 2 mol × 0.0150 mol / 1 mol

X = 0.030 moles of NaI

Hence, it means that NaI is the limiting reagent therefore, it will control the yield of Sodium Nitrate.

Step 3: <u>Find out moles of NaNO₃ formed:</u>

According to equation,

2 mole of NaI produced = 2 moles of NaNO₃

So,

0.020 moles of NaI will produce = X moles of NaNO₃

Solving for X,

X = 2 mol × 0.020 mol / 2 mol

X = 0.020 moles of NaNO₃

Step 4: <u>Calculate Mass of NaNO₃ produced;</u>

As, Moles = Mass / M.Mass

Or,

Mass = Moles × M.Mass

Putting values,

Mass = 0.020 mol × 84.99 g/mol

Mass = 1.70 g of NaNO₃

7 0

3 years ago

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide Al2O3 dissolved in molten c

gtnhenbr [62]

Answer:

1.13 × 10⁶ g

Explanation:

Let's consider the reduction of aluminum (III) from Al₂O₃ to pure aluminum.

Al³⁺ + 3 e⁻ → Al

We can establish the following relations:

1 Ampere = 1 Coulomb / second
The charge of 1 mole of electrons is 96,468 c (Faraday's constant)
1 mole of Al is produced when 3 moles of electrons circulate
The molar mass of Al is 26.98 g/mol.

The mass of aluminum produced under these conditions is:

$90.0 s \times \frac{1s}{620c} \times \frac{96,468c}{1mole^{-} } \times \frac{3mole^{-}}{1molAl} \times \frac{26.98gAl}{1molAl} =1.13 \times 10^{6} g Al$

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What is the pOH of a solution of HNO, that has (OH 1=9,50 * 10M2

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The a is 5 your welcome dude

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What branch of science is concerned with the interaction between matter and electromagnetic radiation?

svp [43]

It’s number 3..................

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