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barxatty [35]
4 years ago
15

Who invented the theory of relativity

Physics
2 answers:
sergeinik [125]4 years ago
8 0
Hii mate____ ^_
.
.

.here's your answer__☺

☆Albert Einstein invented the theory of relativity.
__
HOPE IT HELPS!!
34kurt4 years ago
5 0
Albert Einstein developed the theory of relativity
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a tuck at rest starts to move and accelerated by 4m/s in 25 secondd. what is the velocity of the truck at the end offf the time?
inysia [295]

Answer:

100m/s

Explanation:

4 0
3 years ago
Read 2 more answers
the oxygen you breathe is made up of two oxygen atoms bound together why is oxygen molecule but not componud
steposvetlana [31]
Having more than one atom in its molecule doesn't make
a substance a compound.  It's only a compound if it has
atoms of different elements in its molecule.

Both atoms in an Oxygen molecule are the same element ... Oxygen.
3 0
3 years ago
Why does it takes the outer planets so long to orbit the Sun? Try to come up with two reasons.
tensa zangetsu [6.8K]

well they are normally bigger than the inner planets, and they also have a bigger distance to go


7 0
3 years ago
If I connect an inductor (L) to a capacitor (C), I will get an LC oscillator circuit with some natural frequency omega. If I wer
mart [117]

The new natural frequency would be ω/2.

we know that,

f = \frac{1}{2 pi \sqrt{LC} } = ω.       -> equation 1

now, when capacitance is quadrupled,

f' = \frac{1}{2 pi \sqrt{L ( 4C )} }

f' = \frac{1}{2 pi (2)\sqrt{LC} }.           -> equation 2

substituting value of equation 1 in equation 2 , we get,

f' = \frac{w}{2}

Hence, the new natural frequency of the circuit is ω/2.

what do you mean by frequency ?

The resonant frequency for a particular circuit is the frequency at which this equality stands true. Where L is the inductance in henries and C is the capacitance in farads, this is the  LC circuit's resonant frequency.

Learn more about frequency here:-

brainly.com/question/12530980

#SPJ4

8 0
2 years ago
A satellite is put into an orbit at a distance from the center of the Earth equal to twice the distance from the center of the E
Sveta_85 [38]

Answer:

995 N

Explanation:

Weight of surface, w= 4000N

Gravitational constant, g, is taken as 9.81 hence mass, m of surface is W/g where W is weight of surface

m= 4000/9.81= 407.7472

Using radius of orbit of 6371km

The force of gravity of satellite in its orbit, F=\frac {GMm}{(2r)^{2}}=\frac {GMm}{4(r)^{2}}

Where G=6.67*10^{-11} and M=5.94*10^{24}

F=\frac {(6.67*10^{-11}*5.94*10^{24}*407.7472)}{4*({6.371*10^{6}m)}^{2}}

F= 995.01142 then rounded off

F=995N

6 0
3 years ago
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