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leonid [27]
1 year ago
10

A small boy is playing with a ball on a stationary train. If he places the ball on the floor of the train, when the train starts

moving the ball moves toward the back of the train. Discuss and explain this observation in terms of what you have learned about Newton's Laws.
Physics
1 answer:
expeople1 [14]1 year ago
8 0

A small boy is playing with a ball on a stationary train. If he places the ball on the floor of the train, when the train starts moving the ball moves toward the back of the train. This happened due to inertia

An object at rest remains at rest, or if in motion, remains in motion unless a net external force acts on it .  

When a train starts moving forward, the ball placed on the floor  tends to fall backward is an example of inertia of rest. Due to the reason that the lower part of the ball is in contact with the surface and rest of the part is not . As the train starts moving, its lower part gets the motion as the floor starts moving but the upper part will remain as it is as it is not in contact with the floor , hence do not attain any motion due to the inertia of rest simultaneously i.e. it tends to remain at the same place.

To learn more about inertia here :

brainly.com/question/11049261

#SPJ1

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You pick up a 3.4-kg can of paint from the ground and lift it to a height of 1.8 m. (a) how much work do you do on the can of pa
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(a) For the work-energy theorem, the work done to lift the can of paint is equal to the gravitational potential energy gained by it, therefore it is equal to

W=mg\Delta h

where m=3.4 kg is the mass of the can, g=9.81 m/s^2 is the gravitational acceleration and \Delta h=1.8 m is the variation of height. Substituting the numbers into the formula, we find

W=(3.4 kg)(9.81 m/s^2)(1.8 m)=60.0 J


(b) In this case, the work done is zero. In fact, we know from its definition that the work done on an object is equal to the product between the force applied F and the displacement:

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However, in this case there is no displacement, so d=0 and W=0, therefore the work done to hold the can stationary is zero.


(c) In this case, the work done is negative, because the work to lower the can back to the ground is done by the force of gravity, which pushes downward. Its value is given by the same formula used in part (a):

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