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leonid [27]
2 years ago
10

A small boy is playing with a ball on a stationary train. If he places the ball on the floor of the train, when the train starts

moving the ball moves toward the back of the train. Discuss and explain this observation in terms of what you have learned about Newton's Laws.
Physics
1 answer:
expeople1 [14]2 years ago
8 0

A small boy is playing with a ball on a stationary train. If he places the ball on the floor of the train, when the train starts moving the ball moves toward the back of the train. This happened due to inertia

An object at rest remains at rest, or if in motion, remains in motion unless a net external force acts on it .  

When a train starts moving forward, the ball placed on the floor  tends to fall backward is an example of inertia of rest. Due to the reason that the lower part of the ball is in contact with the surface and rest of the part is not . As the train starts moving, its lower part gets the motion as the floor starts moving but the upper part will remain as it is as it is not in contact with the floor , hence do not attain any motion due to the inertia of rest simultaneously i.e. it tends to remain at the same place.

To learn more about inertia here :

brainly.com/question/11049261

#SPJ1

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I believe it’s D, an applied force.

A reaction force seems to refer to Newton’s third law, but is relatively vague to be the answer to this question.

An expected force isn’t a concept nor the name of any subject of forces that is taught within the physics textbooks.

A positive force refers to direction, a negative force can have less, equal, or even more magnitude than the positive force, thus it contradicts itself. As that’s still a force that can push or pull.

So I believe it to be D.

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A tire is filled with air at 10 ∘C to a gauge pressure of 250 kPa. Part A If the tire reaches a temperature of 45 ∘C, what fract
Alex_Xolod [135]

Answer:

The air fraction to be removed is 0.11

Given:

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Finally its temperature increases, T' = 45^{\circ} = 318 K

Solution:

Using the ideal gas equation:

PV = mRT

where

P = Pressure

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R = Rydberg's Constant

T = Temperature

Now,

Considering the eqn at constant volume and pressure, we get:

mT = m'T'

Thus

\frac{m}{m'} = \frac{T'}{T}                      (1)

Now, the fraction of the air to be removed for the maintenance of pressure at 250 kPa:

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From eqn (1):

y = 1 - \frac{T}{T'}

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