Something must be wrong in the data you have, since this is basic using of linear motion's formulas.
vf=v0+at. Where vf= final velocity; v0= initial velocity, a=acceleration and t=time.
If the rocket is initially at rest, v0=0. Therefore vf=at. Plugging numbers in gives 445=99*4.5, However
445≠445.5.
Check it and then calculate the distance from x=a*t^2.
<span>Your equation for the height of the stone at any time is h(t) = -16t2<span> + 128t + 32 .
From your equation, we can tell that you're defining the upward direction as
positive. We can also tell that you threw the stone upward, with an initial speed
as it left your hand of 128 feet per second, about 87 miles per hour ... a mighty toss indeed, and I think there's a man from the Chicago Cubs waiting outside
who'd like to talk to you.
Anyway, When the stone splashes into the water, h(t) = 0 .
</span></span>
<span>-16t²<span> + 128t + 32 = 0</span></span>
Divide each side by -16 :
t² - 8t - 2 = 0
I don't see any easy way to factor the expression on the left,
so I have to use the quadratic formula to solve this equation.
t = 4 plus and minus √18 .
t = +8.24 seconds
t = -0.24 second
Mathematically, both numbers are valid solutions.But when you apply
the equation to a real world situation, only the positive 't' makes sense.
So <u> t = 8.24 seconds</u>.
7.5 meters
Don’t need to use 980j if you use the correct equations
The attraction force provides the electron's centripetal force.
<span>8.30^-8N = mrω² </span>
<span>ω² = 8.30^-8 / (9.11^-31 kg x 4.70^-11m) .. .. ω² = 1.94^33 (rad/s)² .. .. ω = 4.40^16 rad/s </span>
<span>f = ω/2π = 4.40^16 / 2π .. .. .. ►f = 7.0^15 Hz</span>
Antias speed is about 17.142 km per hour.
60 divided by 3.5. The km divided by the hour gives the km per hour. Hope that helped :)