Answer:
Explanation:
20 km/hr = 5.56 m/s
90 km/hr = 25 m/s
To have just passed C, B must gain first the length of C, then the length of B for a total 400 m
s = s₀ + v₀t + ½at²
if s₀ = 0 at the head of train C when t = 0
for train C, the position in time is
s = 0 + 5.56t + ½(0.2)t²
s = 5.56t + 0.1t²
for train B which must gain 400 m in the same time
s = -400 + 25t + ½(-0.1)t²
s = -400 + 25t - 0.05t²
As both equations equal s, we can set the other sides equal
5.56t + 0.1t² = -400 + 25t - 0.05t²
0.15t² - 19.44t + 400 = 0
quadratic formula positive answer
t = (19.44 + √(19.44² - 4(0.15)(400))) / (2(0.15))
t = 104 s
v = 25 + 104(-0.1) = 14.6 m/s or 52.6 km/hr
Answer:
The formula for Impedance for circuit with R, C, and L are:
The impedance Z of the series RLC circuit depend upon angular frequency ω. Impedance is measured in ohms and resistance (R), inductance reactance and capacitive reactance. Series RLC circuit consist of the resistance, a capacitance and an inductance connected in the circuits. Electrical impedance is the measurement of the opposition that a circuit present in a current.
Answer:
C. tiny particles called charges flowing through the wires.
Explanation:
<h3> Hello!</h3>
An electric current is a stream of charged particles, such as electrons or ions, moving through an electrical conductor or space. It is measured as the net rate of flow of electric charge through a surface or into a control volume.
Hope it helps!
Answer:
option (a)
Explanation:
Wire 1:
length = 2L
Area = 2 A
Wire 2: length = L
Area = A
As we know that the resistance of a wire is directly proportional to the length of the wire and inversely proportional to the area of crossection of the wire.
Let ρ be the resistivity of the cooper wire.
Resistance of wire 1
R1 = ρ x 2L / 2 A = ρ L / A
Resistance of wire 2:
R2 = ρ x L / A = ρ L / A
As R1 = R2
It means both the wires have same resistance.