Answer:
The magnetic field strength is 3.9 x 10⁻³ T
Explanation:
The equation for the magnetic field strength produced by a long straight current-carrying wire is written as;
Where;
μ₀ is constant = 4π x 10⁻⁷ N/A
I is the maximum current = 20 A
r is the radius of the wire = 2.053/2 = 1.0265 mm = 1.0265 x 10⁻³ m
Substitute in this values into the equation above;
Therefore, the magnetic field strength is 3.9 x 10⁻³ T
We have that the instantaneous velocity of the shuttlecock when it hits the ground is
From the question we are told
Assuming the acceleration is still -9.81 m/s2, what is the instantaneous velocity of the
shuttlecock when it hits the ground? Show your work below.
Generally the equation for acceleration is mathematically given as
Where
acceleration is still -9.81 m/s2,
Hence,
Therefore
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