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Harrizon [31]
3 years ago
11

What volume of a concentrated HCl solution, which is 36.0% HCl by mass and has a density of 1.179 g/mL, should be used to make 4

.80 L of an HCl solution with a pH of 1.9
Chemistry
1 answer:
geniusboy [140]3 years ago
7 0

Answer:

5.195 ml

Explanation:

Dissociation of HCl yields;

HCl(aq)   ⇄   H⁺(aq)     +    Cl⁻(aq)

∴ [HCl] = [H⁺] = [Cl⁻]

pH = 1.9

= -log[ H⁺]

= 10^{-pH}

= 10^{-1.9}

= 0.01258 M

Moles of HCl = number of mole × volume

= 0.01258 × 4.80 L

= 0.06042 mole

Mass of HCl = number of moles of HCl  ×  Molar mass of HCl

Mass of HCl = 0.06042 mol ×  36.5 g/mol

Mass of HCl = 2.205 grams

Also, given that the density =  1.179 g/mL

Mass of HCl in the solution = 36% of the density

i.e \frac{36}{100}*1.179

= 0.4244 grams

Volume of a concentrated HCl solution needed can now be determined as;

= \frac{2.205}{0.4244}

= 5.195 ml

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A. The half-life for a first order reaction in 49 minutes. What is the rate constant?B.For a second order reaction, the half-lif
Burka [1]

Answer:

a) 0,014 min⁻¹

b) 1452 seconds.

c) 0,02156 M

d) The faster rate is for the reaction A. The largest rate constant, k, is for A reaction

Explanation:

a) For a first order reaction the half-life is:

t_{1/2} = \frac{ln(2)}{k} <em>(1) </em>As half.life is 49 min. Rate constant -k- is: 0,014 min⁻¹

b) The half-life is defined as the time that takes in descompose the half of the initial concentration of a compound.

As half-life is 726s. In 726s the concentration will be 0,300M, In the next 726s the concentration will be 0,150M. Thus, thae time it takes to decrease concentration until 0,150M is 726s×2= 1452 seconds

c) In the same way, 11072 years are 4 half-life for this reaction, thus:

0,345M/2⁴ = 0,02156 M

d) By definition of half-life, the less half-life, the faster rate. Thus, The faster rate is for the reaction A.

By (1) half-life is inversely proportional to rate constant. Thus, the less half-life, the largest rate constant. The largest rate constant, k, is for A reaction

I hope it helps!

7 0
3 years ago
g chemist accidentally leaves an open beaker containing 250.0 mL of a 0.500 M NaHCO3(aq) solution on a lab bench. They return a
aleksklad [387]

Answer:

1.67 M

Explanation:

The following data were obtained from the question:

Initial volume (V1) of solution = 250 mL

Initial Molarity (M1) of solution = 0.5 M

Final volume (V2) of solution = 75 mL

Final Molarity (M2) of solution =?

Thus, we can obtain the final molarity of the solution by using the following formula:

M1V1 = M2V2

0.5 × 250 = M2 × 75

125 = M2 × 75

Divide both side by 75

M2 = 125 /75

M2 = 1.67 M

Thus, the new Molarity of the solution is 1.67 M.

3 0
3 years ago
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