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sp2606 [1]
3 years ago
16

Graph a system of equations to approximate the value of x, the rate of depreciation. Give your answer as a percent. about 4% abo

ut 13% about 1.2% cannot be determined
Mathematics
2 answers:
muminat3 years ago
9 0

Answer:about 13%

Step-by-step explanation:

Dovator [93]3 years ago
7 0

Answer: about 13% (B)

Step-by-step explanation:

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The answer is B.spin a spinner with 4 equal sections two times

Step-by-step explanation:

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What is the volume of a cereal box that is 2 inches thick, 12 inches high and 10 inches wide?
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240

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12 times 2 is 24

24 times 10 is 240

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Answer: electricity can be used to create magnetism

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3 years ago
A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student
yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

The information provided is as follows:

n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43

The critical value of <em>z</em> for 98% confidence level is,

z_{\alpha/2}=z_{0.02/2}=2.326

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

     =(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0
3 years ago
At the middle school graduation dance, the DJ played 12 slow dances, which was equal to the quotient of the number of fast dance
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quotient means divide

 so 12 = x/2

x = 12*2 = 24

 x =24 fast songs

3 0
3 years ago
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