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3 years ago

16

Graph a system of equations to approximate the value of x, the rate of depreciation. Give your answer as a percent. about 4% abo

ut 13% about 1.2% cannot be determined

2 answers:

muminat3 years ago

9 0

Answer:about 13%

Step-by-step explanation:

Dovator [93]3 years ago

7 0

Answer: about 13% (B)

Step-by-step explanation:

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PLEASE HELLLLP. WILL MARK BRAINLIEST 4 1ST ANSWER

Sever21 [200]

Y=-4/3x-8 that is the equation

8 0

3 years ago

The weight (in pounds) w=f(d) of an object varies inversely as the square of its distance (in thousands of miles) d from the cen

yuradex [85]

The joint variation that is given in the problem above can be expressed as follows:
w = k/d²
where w is the weight, k is the variation constant, and d is the distance from the center of the earth. Substituting the first scenario to obtain the value of k,
160 = k/(4000)²
k = 2.56 x 10^9
Using this value for the second scenario,
w = (2.56 x 10^9) / (8,000)² = 40 lbs
Thus, the weight of the man, 8000 miles above the center of the earth is 40 lbs.

5 0

3 years ago

Parallelograms are four sided figures that have two pairs of opposite, parallel sides. Quadrilateral ABCD

otez555 [7]

Answer:

(A) It would have to lie on AB because DC would rotate halfway around M. B would lie on D and A would lie on C.

(B) AD would lie on the BC line. D would lie on B and A would lie on C.

(C) The Lines CD and AD would only intersect if one line had to rotate 180 degrees around M.

8 0

2 years ago

A bag contains 90 marbles. some green and some transparent. The ratio of green

Archy [21]

Answer:

54 green marbles

Step-by-step explanation:

So green : transparent = 3:2

so 3+2=5 and 3*90/5 = 54 green marbles

8 0

3 years ago

The length of a rectangle is increasing at a rate of 9 cm/s and its width is increasing at a rate of 4 cm/s. When the length is

Setler [38]

Answer:

The area of the rectangle is increasing at a rate of 168 square centimeters per second.

Step-by-step explanation:

Geometrically speaking, the area of a rectangle ( $A$ ), in square centimeters, is described by following expression:

$A = w\cdot l$ (1)

Where:

$w$ - Width, in centimeters.

$h$ - Height, in centimeters.

By Differential Calculus, we find an expression for the rate of change of the area of the rectangle ( $\dot A$ ), in square centimeters per second:

$\dot A = \dot w\cdot l + w\cdot \dot l$ (2)

Where:

$\dot w$ - Rate of change of the width of the rectangle, in centimeters per second.

$\dot l$ - Rate of change of the length of the rectangle, in centimeters per second.

If we know that $w = 12\,cm$ , $l = 15\,cm$ , $\dot w = 4\,\frac{cm}{s}$ and $\dot l = 9\,\frac{cm}{s}$ , then the rate of change of the area of the rectangle is:

$\dot A = \dot w\cdot l + w\cdot \dot l$

$\dot A = 168\,\frac{cm^{2}}{s}$

The area of the rectangle is increasing at a rate of 168 square centimeters per second.

6 0

3 years ago