An element’s atomic number is equal to the number of protons in that element’s nucleus. The mass number is the total number of an atom’s protons and neutrons. Protons have a positive charge; electrons have a negative charge; and neutrons are electrically neutral.
Putting it all together, given that the atomic number of lead is 82, the number of protons a lead atom contains is 82. The number of neutrons would be the difference between 207 and 82, or 125 neutrons. Finally, since you have a neutral atom, there must be an equal number of electrons as the number of protons—that is, 82 electrons.
Thus, you’ve got 82 protons, 125 neutrons, and 82 electrons.
Answer:
<h2>59.1 m</h2>
Explanation:
The height of the object can be found by using the formula

where
p is the potential energy
m is the mass
h is the height
g is the acceleration due to gravity which is 10 m/s²
From the question we have

We have the final answer as
<h3>59.1 m</h3>
Hope this helps you
Answer:
If an insufficient amount of nitrogen were produced, the air bag would under inflate and not provide adequate protection. Clearly, the stoichiometry of the reaction is very important.
Answer:
a) Molar fraction:
Methane: 67,5%
Ethane: 25,1%
Propane: 7,4%
b) Molecular weight of the mixture: 25,16 g/mol
Explanation:
with a basis of 100 kg:
Moles of methane:
500 g ×
= 31,2 moles
Mass of ethane
350 g ×
= 11,6 moles
Mass of propane
150 g ×
= 3,4 moles
Total moles: 31,2 moles + 11,6 moles + 3,4 moles = <em>46,2 moles</em>
Molar fraction of n-methane:
=67,5%
Molar fraction of ethane:
= 25,1%
Molar fraction of propane:
= 7,4%
b) Average molecular weight:
= <em>25,16g/mol</em>
I hope it helps!
Answer:
4.921.
Explanation:
- It is an acidic buffer solution;
∵ pH = pKa + log[salt]/[acid].
<em>∴ pH </em>= - log(1,8 x 10⁻⁵) + log[0.75/0.50] = 4.745 + 0.1761 = <em>4.921.</em>