The sample of the solid in grams is 5.5g
HOW TO CALCULATE SPECIFIC HEAT CAPACITY:
- The quantity of heat absorbed or released by a substance can be calculated using the following formula:
Q = m × c × ∆T
Where;
Q = quantity of heat absorbed/released (cal)
m = mass of the substance (g)
c = specific heat (cal/g°C)
∆T = change in temperature (°C)
- According to the information provided in this question:
Q = 7.90Kcal = 7900cal
m = ?
c = 11.5 cal/g°C
T1 = 135K = 135K − 273.15 = -138.1°C
T2 = 260K = 260K − 273.15 = -13.15°C
∆T = -13.15 - (-138.1) = 124.95°C
- Hence, the mass of the substance can be calculated as follows:
m = Q ÷ c∆T
m = 7900 ÷ (11.5 × 124.95)
m = 7900 ÷ 1436.93
m = 5.5grams.
Therefore, the sample of the solid in grams is 5.5g.
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Answer:
as fast as he wants, ladybugs are useless
Answer:
The size of an object is directly proportional to the gravity
Explanation:
The size of an object has significant impact on the gravity exerted by such a body.
The more massive a body is, the larger the gravity it exerts.
The reason for this is because of the newton's law of universal gravitation.
- It states that "the gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distances between them".
- As such, gravity is directly proportional to mass
The frequency of the human ear canal is 2.92 kHz.
Explanation:
As the ear canal is like a tube with open at one end, the wavelength of sound passing through this tube will propagate 4 times its length of the tube. So wavelength of the sound wave will be equal to four times the length of the tube. Then the frequency can be easily determined by finding the ratio of velocity of sound to wavelength. As the velocity of sound is given as 339 m/s, then the wavelength of the sound wave propagating through the ear canal is
Wavelength=4*Length of the ear canal
As length of the ear canal is given as 2.9 cm, it should be converted into meter as follows:
Then the frequency is determined as
f=c/λ=339/0.116=2922 Hz=2.92 kHz.
So, the frequency of the human ear canal is 2.92 kHz.
