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matrenka [14]
3 years ago
9

Task: Physical and Chemical Properties of Ocean Water

Physics
1 answer:
Taya2010 [7]3 years ago
5 0

Answer:

density

Explanation:

because it high salinity

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Which process helps regulate Earth's climate by transporting warm seawater to colder regions of seawater?
telo118 [61]

Answer: A. Thermohaline circulation

Explanation:

The thermohaline circulation is a phenomena which involves the movement of the oceanic currents because of the differences that occur in the temperature and salinity of oceanic water. These two factors changes the salinity and density of the water and fluctuating the climatic conditions. Cold water is particularly denser than the warm water. The water with more salinity is also denser over water with less salinity. The deep oceanic water currents brings changes in the density as well as the salinity of water hence, the circulation of water is called as thermohaline circulation. Some part of warm water will evaporate from the surface layer of the ocean this will lead to the flow of warm wind currents and water to the regions of cold regions of the seawater.

On the basis of the above description, A. Thermohaline circulation is the correct option.

7 0
3 years ago
Read 2 more answers
A child on a playground swing makes a complete to-and-fro swing each two seconds. the frequency of the swing is
Allisa [31]
0.5 swings per second (0.5 swings/sec if you want it shorter)
7 0
3 years ago
Students repeat the experiment but replace block X and block Y with block W and block Z , as shown in Figure 3. Block W and bloc
Lena [83]
The block Z would be seen in figure 10 when 4 strident turn around
8 0
3 years ago
A 15,000 kg rocket traveling at +230 m/s turns on its engines. Over a 6.0 s period it burns 1,000 kg of fuel. An observer on the
lesya692 [45]

Answer:

a) v = 312.791\,\frac{m}{s}, b) a = 13.333\,\frac{m}{s^{2}}

Explanation:

The problem is asking the rocket velocity and acceleration at t = 6 s.

a) The general equation of the rocket is:

v=v_{o} -v_{ex}\cdot \ln \frac{m}{m_{o}}

v = 230\,\frac{m}{s}-(1200\,\frac{m}{s} )\cdot \ln \frac{14000\,kg}{15000\,kg}

v = 312.791\,\frac{m}{s}

b) The acceleration experimented by the rocket is:

a = \frac{v_{ex}}{m_{o}}\cdot \frac{dm}{dt}

a = \frac{1200\,\frac{m}{s} }{15000\,kg}\cdot \frac{1000\,kg}{6\,s}

a = 13.333\,\frac{m}{s^{2}}

3 0
4 years ago
Read 2 more answers
The compressor in a certain Carnot refrigerator performs 580 J of work to remove 150 J of heat from the interior of the refriger
irga5000 [103]

Answer:

Explanation:

Given:

Workdone by the system, Win = 580 J

Workdone consumed, W = 150 J

Heat loss, Wout = Win - W

= 580 - 150

= 430 J

Heat lost by the coils of the refrigerator to the kitchen = 430 J.

6 0
3 years ago
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