Answer:
3 m/s²
Explanation:.
To solve this, we use the formula of tangential acceleration. The tangential acceleration is given by the following equation:
a(t) = r * a(a)
where
a(t) is the tangential acceleration, m/s²
r is the radius, m
a(a) is the angular acceleration, rad/s²
Again, we know that the radius can be gotten by saying r = d/2, thus, r = 1.2/2 = 0.6 m
We then multiply this by the angular acceleration, to get our tangential acceleration
a(t) = 0.6 * 5 = 3 m/s²
Therefore, the Tangential acceleration of a point on the flywheel rim has been found to be 3 m/s²
Answer:
1.74 m/s
Explanation:
From the question, we are given that the mass of the an object, m1= 2.7 kilogram(kg) and the mass of the can,m(can) is 0.72 Kilogram (kg). The velocity of the mass of an object(m1) , V1 is 1.1 metre per seconds(m/s) and the velocity of the mass of can[m(can)], V(can) is unknown- this is what we are to find.
Therefore, using the formula below, we can calculate the speed of the can, V(can);
===> Mass of object,m1 × velocity of object, V1 = mass of the can[m(can)] × velocity is of the can[V(can)].----------------------------------------------------(1).
Since the question says the collision was elastic, we use the formula below
Slotting in the given values into the equation (1) above, we have;
1/2×M1×V^2(initial velocity of the first object) + 1/2 ×M(can)×V^2(final velocy of the first object)= 1/2 × M1 × V^2 m( initial velocity of the first object).
Therefore, final velocity of the can= 2M1V1/M1+M2.
==> 2×2.7×1.1/ 2.7 + 0.72.
The velocity of the can after collision = 1.74 m/s
Answer:
291 K is the answer
Explanation:
to get Kelvin from Celsius use the following
Kelvin = Celsius +273
= 18 +273
= 291
