Boiling-point elevation is a colligative property.
That means, the the boiling-point elevation depends on the molar content (fraction) of solute.
The dependency is ΔTb = Kb*m
Where ΔTb is the elevation in the boiling point, kb is the boiling constant, and m is the molality.
A solution of 6.00 g of Ca(NO3) in 30.0 g of water has 4 times the molal concentration of a solution of 3.00 g of Ca(NO3)2 in 60.0 g of water.:
(6.00g/molar mass) / 0.030kg = 200 /molar mass
(3.00g/molar mass) / 0.060kg = 50/molar mass
=> 200 / 50 = 4.
Then, given the direct proportion of the elevation of the boiling point with the molal concentration, the solution of 6.00 g of CaNO3 in 30 g of water will exhibit a greater boiling point elevation.
Or, what is the same, the solution with higher molality will have the higher boiling point.
Answer:
Sample C is most likely the metal.
Explanation:
The Sample C is the metal, because the properties given in the sample c are all of the metal. As we know that the metals are the lustrous or the shiny elements. They are often good conductor of heat and also electricity. The metals possess high melting point. The density of the metals are heavy for their size. Metals can be easily hammered, and hence are malleable. They can easily be stretched into wires hence are ductile. They remains solid at room temperature but in case of mercury it remains as liquid. Metals are opaque object and cannot be see through it.
I think it'd because of (4), the reactivity of gold atoms, or rather, it's unreactivity. Gold, unlike most metals, doesn't form an oxide layer when exposed to air (Which is why it's so valued in jewellery, the metal will never tarnish, only stay gold forever). This makes it weaker, and so it can be formed in to thinner sheets.
However, (3), the nature of bonds between gold atoms also allows for the metal to be flattened, as metallic bonds aren't amazingly strong, and allow for metals to bend. This is what makes pure metals so weak, and why we use alloys.
Answer:
See figure 1
Explanation:
In this question, we have to remember that a <u>poor electron carbon is a carbon in which we have a positive charge</u>, a carbocation. Therefore we have to start with the production of the carbocation. First, a double bond from the benzene is moved to the carbon in the top to produce a new double bond generating a positive charge in a carbon with <u>ortho position</u> (electron-poor). Then we can move another double bond inside the ring to produce a positive charge in the <u>para carbon.</u> Finally, we can move the last double bond to produce again another positive charge in the <u>second ortho carbon.</u>
See figure 1.
I hope it helps!