Answer:
They move to an area where they are less concentrated
Explanation:
In a cell the surface that separates the system from the surrounding environment is the cell membrane and the exchange of substances between the cell and the medium must occur through this membrane. This exchange is essential to maintain the integrity of the cell and to provide the different chemical species necessary for the metabolic processes that occur permanently within it. As we saw, substances move driven by their gradient of chemical or electrochemical potential. Every substance is formed by molecules that have a certain amount of thermal energy that is indicative of their spontaneous movements, a result of thermal movement is diffusion. A large part of the passage of molecules through the cell membrane is produced by simple diffusion. When one molecule is more concentrated on one side of the membrane than on the other and the membrane is permeable to it, there is a tendency for the molecule to diffuse through the membrane in favor of its concentration gradient. This dezplacement occurs without external energy expenditure (passive transport).
An important example is the oxygen uptake of a cell by performing cellular respiration. Dissolved oxygen diffuses into the cell through the cell membrane. As cellular respiration consumes the entering O2, diffusion within the cell will continue because the concentration gradient favors movement in that direction. The same happens, but in the opposite direction, with carbon dioxide. Then you can see the process in the following animation.
In simple diffusion through a biological membrane, small non-polar solute molecules (no charge) move directly through the membrane in favor of their concentration gradient. Oxygen and carbon dioxide can diffuse rapidly through the membrane. The simple diffusion rate is directly related to the solute concentration; The more concentrated the solute, the faster the diffusion.
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No work is done by THAT force.
Answer:
The average force has a magnitude 6524 N due north.
Explanation:
The average net force F = ma where m = mass of car = 1400 kg and a = acceleration.
a = (v - u)/t where u = initial velocity of car = 0 m/s (since it starts from rest)
v = final velocity of car = 27 m/s due north and t = time of motion = 5.8 s
a = (27 m/s - 0 m/s)/5.8 s = 27 m/s ÷ 5.8 s = 4.66 m/s
Since the direction of the velocity change is the direction of the acceleration, the acceleration is 4.66 m/s due north.
The average force, F = ma = 1400 kg × 4.66 m/s = 6524 N
Since the acceleration is due north, the average force takes the direction of the acceleration.
So the direction of the average force is due north
The average force has a magnitude 6524 N due north.
The initial acceleration of the wishbone is 13.1 m/s².
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Acceleration:</h3>
This can be defined as the rate of change of velocity. The S.I unit of acceleration is m/s²
To calculate the acceleration of the wishbone, we use the formula below.
⇒ Formula:
- F' = ma........................... equation 1
⇒ Where:
- F' = Net force between Kevin and Gamal
- m = mass of the wishbone
- a = acceleration of the wishbone
⇒ make a the subject of the equation
- a = F'/m....................... Equation 2
From the question,
⇒ Given:
- F' = 0.17 N
- m = 13 g = 0.013 kg
⇒ Substitute these values into equation 2.
- a = 0.17/0.013
- a = 13.1 m/s²
Hence, The initial acceleration of the wishbone is 13.1 m/s².
Learn more about acceleration here: brainly.com/question/605631