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irina [24]
3 years ago
7

An electromagnetic radio wave is received by a transmitter before it is converted to a sound wave. The radio wave has a waveleng

th of 23,076 m and a frequency of 13,000 Hz. What velocity is the wave traveling at before the transmitter converts it to a sound wave?a. 1.76 m/sb. 0.56 m/sc. 3.31 × 102 m/sd. 3.00 × 108 m/s
Physics
1 answer:
Dennis_Churaev [7]3 years ago
3 0

Answer:

h5

Explanation:

h65hhrhry

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I throw a football in the x direction with a fore of 124N. The football is 4 kilograms. The football accelerated for 5 seconds.
castortr0y [4]

31 (unit)

acceleration formula

                             net force (124)

     Acceleration = -------------

                                mass     (4)

124÷4=31

6 0
3 years ago
Suppose the collision between the packages is perfectly elastic. To what height does the package of mass m rebound?
Hitman42 [59]

The height, h to which the package of mass m bounces to depends on its initial velocity, v and the acceleration due to gravity, g and is given below:

h = \frac{v^{2}}{2g}

<h3>What are perfectly elastic collision?</h3>

Perfectly elastic collisions are collisions in which the momentum as well as the energy of the colliding bodies is conserved.

In perfectly elastic collisions, the sum of momentum before collision is equal to the momentum after collision.

Also, the sum of kinetic energy before collision is equal to the sum of kinetic energy after collision.

Since some of the Kinetic energy is converted to potential energy of the body;

\frac{mv^{2}}{2} = mgh

h = \frac{v^{2}}{2g}

Therefore, the height to which the package m bounces to depends on its initial velocity and the acceleration due to gravity.

Learn more about elastic collisions at: brainly.com/question/7694106

7 0
2 years ago
2. What is equal to the kinetic energy of a car with a mass of 0.5t (tonne) if it travels
GalinKa [24]

Answer:

7.14kg/h

Explanation:

=500kg/70h

=7.14kg/h

7 0
3 years ago
A ball of radius R and mass m is magically put inside a thin shell of the same mass and radius 2R. The system is at rest on a ho
dlinn [17]

Answer:

x =\frac{-R}{2}

Explanation:

From the question we are told that mass

Thin layer radius = 2R

Generally the expression for ths solution is given as

Xcm =(m*0 =m(-2R))/2m =-mR/(2m)=-R/2

the center of mass will not move at initial state  

Considering the center of mass of both bodies

xcm=\frac{m*x+m*x)}{2m} =x

x =\frac{-R}{2}

Therefore the enclosing layer moves x =\frac{-R}{2}                          

7 0
3 years ago
The mass of the boy is 35 kilograms. What is the force of friction that slowed him down?
pychu [463]

Answer:

Newton's F=ma, which means the force (F) acting on an object is equal to the mass (m) of an object times its acceleration (a)

3 0
3 years ago
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