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gulaghasi [49]
3 years ago
6

A building superintendent twirls a set of keys in a circle at the end of a cord. If the keys have a centripetal acceleration of

114 m/s2 and the cord has a length of 0.29 m, what is the tangential speed of the keys? Answer in units of m/s.
Physics
1 answer:
maria [59]3 years ago
8 0

Answer:

5.75m/s

Explanation:

The formula we need to use here is the formula of centripetal acceleration given as

a=v^{2} /r

we have the acceleration and the radius (luckly in the units we need them to be)

replacing it would yield

114m/s^{2} =v^{2} /0.29m

then solving for v

\sqrt{114m/s^{2} * 0.29m }= v

\sqrt{33 m^{2} / s^{2}}= v\\ 5.75 m/s = v

(notice how m/s^{2} * m yields m^{2}/s^{2} which when applying the square root yield m/s)

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Read the scenario and solve these two problems.
Burka [1]

Answers:

a) 5400000 J

b) 45.92 m

Explanation:

a) The kinetic energy K of an object is given by:

K=\frac{1}{2}mV^{2}

Where:

m=12000 kg is the mass of the train

V=30 m/s is the speed of the train

Solving the equation:

K=\frac{1}{2}(12000 kg)(30 m/s)^{2}

K=5400000 J This is the train's kinetic energy at its top speed

b) Now, according to the Conservation of Energy Law, the total initial energy is equal to the total final energy:

E_{i}=E_{f}

K_{i}+P_{i}=K_{f}+P_{f}

Where:

K_{i}=5400000 J is the train's initial kinetic energy

P_{i}=0 J is the train's initial potential energy

K_{f}=0 J is the train's final kinetic energy

P_{f}=mgh is the train's final potential energy, where g=9.8 m/s^{2} is the acceleration due gravity and h is the height.

Rewriting the equation with the given values:

5400000 J=(12000 kg)(9.8 m/s^{2})h

Finding h:

h=45.918 m \approx 45.92 m

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3 years ago
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They are based on layers of rock the correspond to certain time periods, so my guess would be D.
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A 0.12 kg body undergoes simple harmonic motion of amplitude 8.5 cm and period 0.20 s. (a) What is themagnitude of the maximum f
Neporo4naja [7]

Answer:

a)F=698.83 N

b)K=8221.56 N/m

Explanation:

Given that

mass ,m = 0.12 kg

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We know that

T=\dfrac{2\pi}{\omega}

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We know that

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K=\dfrac{\omega^2}{m}

K=\dfrac{31.41^2}{0.12}\ N/m

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F= K A

F= 8221.56 x 0.085 N

F=698.83 N

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lakkis [162]

Answer: the first one

Explanation: good luck!

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Answer:

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