All categories

3 years ago

. What is the height in meters of a 5'4" person?

Physics

1 answer:

Illusion [34]3 years ago

5 0

Answer:

1.62 meters

Explanation:

For an approximate result, divide the feet (height) by 3.3 to get your approximate meters (height).

You might be interested in

Which characteristics is common to the four outer planets in out solar system ?

Lubov Fominskaja [6]

I think the answer is B

8 0

3 years ago

Read 2 more answers

A gazelle is running at 17.46 m/s. He sees a lion and accelerates at -1.49 m/s/s,

Vsevolod [243]

Answer:

V=21.0211m/s

Explanation:

Use V=vi+at

So, V=17.46m/s+(1.49m/ $s^{2}$ )(2.39s)= 21.0211m/s

5 0

2 years ago

Read 2 more answers

Eddie and Val observed the picture of an athlete running in a race.

dedylja [7]

Answer:

Your answer would be C <u><em>Hope this helps</em></u>

8 0

3 years ago

What is the difference between melting point and boiling point?

castortr0y [4]

Melting point is when a mass goes from solid to liquid, whereas boiling point is when a mass goes from liquid to gas. I hope this helps.

8 0

3 years ago

A car accelerates from rest at 1.0 m/s2 for 20.0 second along a straight road. It then moves at a constant speed for half an hou

Whitepunk [10]

Total distance = 36500 m

The average velocity = 19.73 m/s

<h3>Further explanation</h3>

Given

vo=initial velocity=0(from rest)

a=acceleration= 1 m/s²

t₁ = 20 s

t₂ = 0.5 hr = 1800 s

t₃= 30 s

Required

Total distance

Solution

State 1 : acceleration

$\tt d=vo.t+\dfrac{1}{2}at^2\\\\d=\dfrac{1}{2}\times 1\times 20^2\rightarrow vo=0\\\\d=200~m$

$\tt vt=vo+at\\\\vt=at\rightarrow vo=0\\\\vt=1\times 20\\\\vt=20~m/s$

State 2 : constant speed

$\tt d=v\times t\\\\d=20\times 1800\\\\d=36000~m$

State 3 : deceleration

$\tt vt=vo+at\rightarrow vt=0(stop)\\\\vo=-at\\\\20=-a.30~s\\\\a=-\dfrac{2}{3}m/s^2(negative=deceleration)$

$\tt d=vot+\dfrac{1}{2}at^2\\\\d=20.30-\dfrac{1}{2}.\dfrac{2}{3}.30^2\\\\d=300~m$

Total distance : state 1+ state 2+state 3

$\tt 200 + 36000 + 300=36500~m$

the average velocity = total distance : total time

$\tt avg~velocity=\dfrac{36500}{20~s+1800~s+30~s}=19.73~m/s$

4 0

3 years ago

. What is the height in meters of a 5'4" person?​

. What is the height in meters of a 5'4" person?