Question

you hold in your hand a block of material with 3x10^27 protons , 3x10^37 neutrons , and 3.1x10^27 electrons. what is the mass of the block , and what is its charge

Answer 1

1) The total mass is $5.01\cdot 10^{10} kg$

2) The total charge is $-1.6\cdot 10^{-7} C$

Explanation:

1)

To calculate the total mass of the particles, we have to write down the mass of each particle first:

Proton: $m_p = 1.67\cdot 10^{-27} kg$

Neutron: $m_n = 1.67\cdot 10^{-27} kg$

Electron: $m_e = 9.11\cdot 10^{-31} kg$

Here we have:

3x10^27 protons

3x10^37 neutrons

3.1 x10^27 electrons

So, the total mass is:

$M=(3\cdot 10^{27})m_p + (3\cdot 10^{37})m_n + (3.1\cdot 10^{27})m_e=5.01\cdot 10^{10} kg$

2)

To calculate the total charge of the particles, we have to write down the charge of each particle first:

Proton: $q_p = 1.6 \cdot 10^{-19}C$

Neutron: $q_n = 0$

Electron: $q_e = -1.6\cdot 10^{-19}C$

Here we have:

3x10^27 protons

3x10^37 neutrons

3.1 x10^27 electrons

So, the total charge is:

$Q=(3\cdot 10^{27})q_p + (3\cdot 10^{37})q_n + (3.1\cdot 10^{27})q_e=-1.6\cdot 10^{-7} C$

Learn more about protons, neutrons and electrons:

brainly.com/question/2757829

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