Question

As seen from above, a playground carousel is

Answer 1

Answer:

The final angular speed of the carousel is 1.68 rad/s.

Explanation:

This is simply a conservation of angular momentum problem.

$\vec{L}_0 = \vec{L}_1\\L_0 = I_0\omega_0 = 125*3.14 = 392.5\\L_1 = I_1\omega_1 = (mR^2 + I_0)\omega_1 = (48*1.5^2 + 125)\omega_1 = 233\omega_1$

Combining the two equations yields the angular momentum of the carousel after the man climbs.

$392.5 = 233\omega_1\\\omega_1 = 1.68~rad/s$