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Alexxandr [17]
3 years ago
12

The temperature of 15.71 grams of gold rises from 32°C to 1,064°C, and then the gold melts completely. If gold’s specific heat i

s 0.1291 joules/gram degree Celsius and its heat of fusion is 63.5 joules/gram, how much energy is gained by the gold? The gold gained a total of joules of energy.
Chemistry
1 answer:
antoniya [11.8K]3 years ago
6 0

Answer:Total energy gained by 15.71 g is 3090.6471 joules

Explanation:

Given:

Q = heat gained by the 15.71 gram mass of gold

Q=mc\Delta T +m\Delta H_{fusion}

\Delta T=(T_{final}-T_{initial})=(1064^oC-32^oC)=1032^oC

c = specific heat capacity of gold = 0.1291joules/gram^oC

m = mass of gold =15.71 g

Q=15.71 g\times 0.1291 joules/gram^oC (1032^oC) +15.71 g\times 63.5 Joules/gram

Heat gained by gold = 2093.0621 Joules + 997.585 Joules

=3090.6471 joules

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Answer:

An atom is a particle of matter that uniquely defines achemical element. An atom consists of a central nucleus that is usually surrounded by one or more electrons. Each electron is negatively charged. The nucleus is positively charged, and contains one or more relatively heavy particles known as protons and neutrons.

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2 years ago
Part of the solution that is présent in the largest amount is the
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Answer:

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3 0
2 years ago
In the reaction of aluminum metal and oxygen to make aluminum oxide, how many grams of oxygen gas will react with 2.2 moles alum
sweet-ann [11.9K]

Answer:

52.8 g of O2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

4Al + 3O2 —> 2Al2O3

From the balanced equation above,

4 moles of Al reacted with 3 moles of O2 to produce 2 moles of Al2O3

Next, we shall determine the number of mole of O2 needed to react with 2.2 moles of Al. This can be obtained as follow:

From the balanced equation above,

4 moles of Al reacted with 3 moles of O2.

Therefore, 2.2 moles of Al will react with = (2.2 × 3)/4 = 1.65 moles of O2.

Thus, 1.65 moles of O2 is needed for the reaction.

Finally, we shall determine the mass of O2 needed as shown below:

Mole of O2 = 1.65 moles

Molar mass of O2 = 2 × 16= 32 g/mol

Mass of O2 =?

Mole = mass/Molar mass

1.65 = mass of O2 /32

Cross multiply

Mass of O2 = 1.65 × 32

Mass of O2 = 52.8 g

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4 0
2 years ago
2. A copper wire can conduct electricity whether the wire is
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Intensive

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7 0
2 years ago
For IR radiation with û = 1,130 cm 1, v=__THz
Dmitry [639]

<u>Answer:</u> The frequency of the radiation is 33.9 THz

<u>Explanation:</u>

We are given:

Wave number of the radiation, \bar{\nu}=1130cm^{-1}

Wave number is defined as the number of wavelengths per unit length.

Mathematically,

\bar{\nu}=\frac{1}{\lambda}

where,

\bar{\nu} = wave number = 1130cm^{-1}

\lambda = wavelength of the radiation = ?

Putting values in above equation, we get:

1130cm^{-1}=\farc{1}{\lambda}\\\\\lambda=\frac{1}{1130cm^{-1}}=8.850\times 10^{-4}cm

Converting this into meters, we use the conversion factor:

1 m = 100 cm

So, 8.850\times 10^{-4}cm=8.850\times 10^{-4}\times 10^{-2}=8.850\times 10^{-6}m

  • The relation between frequency and wavelength is given as:

\nu=\frac{c}{\lambda}

where,

c = the speed of light = 3\times 10^8m/s

\nu = frequency of the radiation = ?

Putting values in above equation, we get:

\nu=\frac{3\times 10^8m/s}{8.850\times 10^{-4}m}

\nu=0.339\times 10^{14}Hz

Converting this into tera Hertz, we use the conversion factor:

1THz=1\times 10^{12}Hz

So, 0.339\times 10^{14}Hz\times \frac{1THz}{1\times 10^{12}Hz}=33.9THz

Hence, the frequency of the radiation is 33.9 THz

7 0
2 years ago
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