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-Dominant- [34]
3 years ago
14

When a man walks across the carpet and reaches for the door knob, why does he get shocked? doorknob Question 3 options: There is

an electric current in the door knob The carpet was exposed to electricity. Atoms are moving faster in the door knob than in his hand When he drags his feet across the carpet he gains an electric charge, and then the electrons jump from his hand to the doorknob.
Physics
1 answer:
Mumz [18]3 years ago
3 0

The imbalance of electric charges within or on the surface of a material or between materials is known as static electricity. When you grab a doorknob, electrons jump from your hand to the knob .which conducts electricity, giving you a shock.

<h3>What is static electricity?</h3>

The imbalance of electric charges within or on the surface of a material or between materials is known as static electricity.

The charge will persist until it can be moved away by an electric current or an electrical discharge.

when we walk on the carpet with socks our feet slide electrons off the carpet.  it leads to leaving you with a slightly negative static charge.

When you grab a doorknob electrons jump from your hand to the knob which conducts electricity giving you a shock.

Due to the static electricity jump from your hand to the knob .which conducts electricity giving you a shock.

To know more about static electricity refer to the link ;

brainly.com/question/821085

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loris [4]

Answer:

She would travel 175.5 m in the same amount of time

Explanation:

Here is the complete question:

Seven bicyclist are racing. Each bicyclist rides for 9s. If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 39m/s, how far would she travel during the race in the same amount of time)?

Explanation:

To determine how far she would travel in the same amount of time, that is the distance she would cover in the same amount of time

From the question,

The bicyclist has an initial velocity of zero

That is, u = 0 m/s

and a final velocity of 39 m/s

That is, v = 39 m/s

Each bicyclist rides for 9s,

She also traveled for the same amount of time

that is, t = 9s

To determine the distance,

From one of the equations of motion for linear motion

s = \frac{1}{2} t(u + v)

Then

s = \frac{1}{2} (9)(0+39)

s = 4.5 (39)

s = 175.5 m

Hence, she would travel 175.5 m in the same amount of time

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