The correct match of each item to the clean water regulation it describes is as follows:
- Regulates pollutants discharged into surface waters: Clean water act
- Covers both surface and ground waters: Safe drinking water act
- Authorizes the EPA to establish minimum standards for tap water: Safe drinking water act
- Funds sewage treatment plants: Clean water act
<h3>What are the functions of clean water regulation?</h3>
Clean Water Act (CWA) is a regulatory body that establishes the basic structure for the regulation of pollutants discharge and maintenance of quality standards of the surface waters.
On the other hand, the Safe Drinking Water Act was founded to oversee the protection of the quality drinking water. The regulatory body is primarily concerned with potable water all waters, whether from above ground or underground sources.
Therefore, the correct match of each item to the clean water regulation it describes is as follows:
- Regulates pollutants discharged into surface waters: Clean water act
- Covers both surface and ground waters: Safe drinking water act
- Authorizes the EPA to establish minimum standards for tap water: Safe drinking water act
- Funds sewage treatment plants: Clean water act
Learn more about clean water regulation at: brainly.com/question/2142268
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Let us situate this on the x axis, and let our uniform line of charge be positioned on the interval <span>(−L,0]</span> for some large number L. The voltage V as a function of x on the interval <span>(0,∞)</span> is given by integrating the contributions from each bit of charge. Let the charge density be λ. Thus, for an infinitesimal length element <span>d<span>x′</span></span>, we have <span>λ=<span><span>dq</span><span>d<span>x′</span></span></span></span>.<span>V(x)=<span>1/<span>4π<span>ϵ0</span></span></span><span>∫line</span><span><span>dq/</span>r</span>=<span>λ/<span>4π<span>ϵ0</span></span></span><span>∫<span>−L</span>0</span><span><span>d<span>x/</span></span><span>x−<span>x′</span></span></span>=<span>λ/<span>4π<span>ϵ0</span></span></span><span>(ln|x+L|−ln|x|)</span></span>
Answer:
an armature a permanent magnet brushes slip rings
Explanation:
Easy !
Take any musical instrument with strings ... a violin, a guitar, etc.
The length of the vibrating part of the strings doesn't change ...
it's the distance from the 'bridge' to the 'nut'.
Pluck any string. Then, slightly twist the tuning peg for that string,
and pluck the string again.
Twisting the peg only changed the string's tension; the length
couldn't change.
-- If you twisted the peg in the direction that made the string slightly
tighter, then your second pluck had a higher pitch than your first one.
-- If you twisted the peg in the direction that made the string slightly
looser, then your second pluck had a lower pitch than the first one.
