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Andreas93 [3]
3 years ago
10

Activity

Physics
1 answer:
vodka [1.7K]3 years ago
5 0
Your welcome LOL plz like

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Which is the poorest conductor of energy
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Insulators are the poorest conductor of energy
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4 years ago
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The energy wasted in using a machine is 600j. if the machine is 70% efficient. calculate the volume of water pumb by the machine
WINSTONCH [101]

Answer:

yhgigy6ftu5cg l8vbbnnbbgtccccvhklhaywje nc 62bbnzmakbdbvfvdbf93bdldmffmfkqhdv

3 0
3 years ago
6. What makes an electromagnet stronger than a solenoid?
qwelly [4]

Answer:

7.

1.wrapping the coil around a piece of iron (such as an iron nail)

2.adding more turns to the coil.

3.increasing the current flowing through the coil.

6.What makes an electromagnet stronger than a solenoid? There is a ferromagntic material inside the solenoid that is magnetized and adds to the strength of the magnetic field produced by the current alone. ... Wind the coils of the solenoid closer together.

3 0
4 years ago
A cart is initially moving at 0.5 m/s along a track. The cart comes to rest after traveling 1 m. The experiment is repeated on t
Anuta_ua [19.1K]

Answer:

D. 4 m

Explanation:

According to the work-energy theorem, the work done by the force acting on a body modifies its kinetic energy.

W=\Delta K\\W=K_f-K_i\\W=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}

The car comes to rest after a given distance, so v_f=0. Recall the definition of work W=Fdcos\theta, here F is the constant force acting on the car, d is its traveled distance and \theta is the angle between the force and the displacement, since friction force acts opposite to the direction of motion \theta=180^\circ :

-Fd=-\frac{mv_i^2}{2}\\d=\frac{mv_i^2}{2F}

We have:

v_i'=1\frac{m}{s}\\v_i=0.5\frac{m}{s}\\v_i'=2vi

Thus:

d'=\frac{2m(v_i')^2}{2F}\\d'=\frac{2m(2v_i)^2}{2F}\\d'=4\frac{2mv_i^2}{2F}\\d'=4d\\d'=4(1m)\\d'=4m

6 0
3 years ago
(a) and (b) ??Thanks <br>HELP <br>d8 =1​
garri49 [273]

Explanation:

(a) You can solve this using kinematics or energy.

Using kinematics:

a = F/m = 90 N / 4 kg = 22.5 m/s²

v₀ = 0 m/s

Δx = 5 m

Find: v

v² = v₀² + 2aΔx

v² = (0 m/s)² + 2 (22.5 m/s²) (5 m)

v = 15 m/s

Using energy:

W = ΔKE

Fd = ½ mv²

(90 N) (5 m) = ½ (4 kg) v²

v = 15 m/s

(b) ΔU = mg Δh

ΔU = (4 kg) (9.8 m/s) (12 m sin 40° − 15 m)

ΔU = -290 J

W = ΔU = -290 J

7 0
3 years ago
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