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3 years ago

A body oscillates with simple harmonic motion accordingto the

Physics

1 answer:

gregori [183]3 years ago

8 0

Answer:(a) displacement= 6.0m

(b) velocity = 8.996m/s

(d) phase of motion= 2.999

(e) frequency= 1.499hz

(f) period of motion= 0.667sec

Explanation:Given that,

X= (6.0m) cos (3πrad/s)t + π/3rad...(i)

Compare equation (i) to wave equation,

Y= A cos (wt) + kx...(ii)

(a) displacement which is also known as amplitude A. So by comparing equation (i) & (ii), we have A= 6.0m

Therefore,displacement= 6.0m

(b) velocity=B/T (where B= wavelength and T=period)

Wavelength B=2π/k (where k=π/3,comparing the two equations)

Therefore, wavelength B=2π÷π/3=6

Period T= 2π/w (where w=3π,comparing the two equations)

Therefore, period T=2π÷3π=0.667sec

Therefore, Velocity V=B/T=6/0.667=8.996m/s

(d)phase of motion=t/T (where t= elapsed time and T=period)

T=0.667sec ( from (c) solving for velocity)

t=2.0s, as given in the question

Therefore, phase of motion= t/T=2/0.667=2.999

(e) frequency=1/T (where T is the period)

T=0.667secs (recall from (c) while solving for velocity)

Therefore, frequency=1/T=1/0.667=1.499hz

(f) period=1/f (where f= frequency)

Therefore, period=1/f=1/1.499=0.667secs.

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The correct answer is iii

Problem 2

For this problem we have two possibilities the lens is convergent or divergent, in both cases the back face (R₂) must be flat

Case 1 Flat lens - convex (convergent)

R₂ = infinity

R₁ > 0

Cas2 Flat-concave (divergent) lens

R₂ = infinity

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