Two positive charges of magnitude 20 micro C and 100 micro C are placed at a distance of 150cm. Calculate the electric force of
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Answer:
y = 0.1 m
Explanation:
The electrical power for point loads is
V = k Sum qi / ri
in this case
V = k ()
indicate that V = 0
r₂ =
the distance r1 is
r₁ = y -0
the distance r2
r₂ = 0.14 -y
we substitute
0.14 - y = y
y ( ) = 0.14
y 1.4 = 0.14
y = 0.14 / 1.4
y = 0.1 m