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amid [387]
3 years ago
8

Explain how plantesimals differ from protoplanets

Chemistry
1 answer:
MAXImum [283]3 years ago
5 0

Answer:

Planetesimals are solid objects thought to exist in protoplanetary disks and in

A protoplanet is a large planetary embryo that originated within a protoplanetary disc and has undergone internal melting to produce a differentiated interior.

You might be interested in
How does cold water affect the speed of dissolving?
sineoko [7]

Answer:

Anything that can be done to increase the frequency of those collisions and/or to give those collisions more energy will increase the rate of dissolving.

Explanation:

depended on the temperature

4 0
2 years ago
2Mg + O2à MgO For this unbalanced chemical equation, what is the coefficient for oxygen when the equation is balanced? A. 1 B. 2
Vikki [24]

Answer:

The answer to your question is the letter A. 1

Explanation:

Unbalanced chemical reaction

                      Mg  +  O₂  ⇒  MgO

               Reactants    Elements    Products

                       1            Magnesium       1

                       2           Oxygen              1

Balanced chemical reaction

                      2Mg  +  O₂  ⇒  2MgO

              Reactants    Elements    Products

                       2           Magnesium       2

                       2           Oxygen             2

Conclusion

The coefficients of the balanced equation are 2, 1, 2

7 0
2 years ago
Read 2 more answers
Will mark as brainiest <br> Please help
Levart [38]

Answer:

  1. metal sulfate
  2. metal sulfate
  3. copper sulfate
  4. copper nitrate
  5. copper chloride
  6. copper phosphate
  7. hydrochloric acid, water
  8. Potassium, sulfuric acid, water

(Correct me if I am wrong)

4 0
2 years ago
Read 2 more answers
A gas has a volume of 1.75L at -23°C and 150.0 kPa. At what temperature would the gas occupy 1.30L at 210.0 kPa?
Nastasia [14]

Answer:

At -13 ^{0}\textrm{C} , the gas would occupy 1.30L at 210.0 kPa.

Explanation:

Let's assume the gas behaves ideally.

As amount of gas remains constant in both state therefore in accordance with combined gas law for an ideal gas-

                                          \frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

where P_{1} and P_{2} are initial and final pressure respectively.

           V_{1}  and V_{2} are initial and final volume respectively.

           T_{1} and T_{2} are initial and final temperature in kelvin scale respectively.

Here P_{1}=150.0kPa , V_{1}=1.75L , T_{1}=(273-23)K=250K, P_{2}=210.0kPa and V_{2}=1.30L

Hence    T_{2}=\frac{P_{2}V_{2}T_{1}}{P_{1}V_{1}}

            \Rightarrow T_{2}=\frac{(210.0kPa)\times (1.30L)\times (250K)}{(150.0kPa)\times (1.75L)}

            \Rightarrow T_{2}=260K

            \Rightarrow T_{2}=(260-273)^{0}\textrm{C}=-13^{0}\textrm{C}

So at -13 ^{0}\textrm{C} , the gas would occupy 1.30L at 210.0 kPa.

5 0
3 years ago
QUICK! WILL MARK BRAINLIEST
nalin [4]

Answer:

Ability to be bent = Malleability

Identity = Physical Change

Electrical Current = Conductivity

Dissolve = Solubility

Color, Phase, or Hardness = Physical Property

5 0
2 years ago
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