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4 years ago

When Nina jumps into the air, the Earth pulls her back down through the force of gravity. What else occurs?

Physics

2 answers:

Alex Ar [27]4 years ago

5 0

It is A. hope this helps

Nookie1986 [14]4 years ago

5 0

1) WRONG. Since gravitational force is an attractive force.
2) WRONG. The Earth does accelerate but the acceleration is so small that it's negligible. However it DOES ACCELERATE.
3) CORRECT.
4) WRONG. Mass means gravitational field, so Nina might be small compared to the Earth but it still creates a gravitational field around her. This answer is also wrong because it's breaking Newton's third law of action-reaction. If Earth pulls Nina, then Nina pulls the Earth back with the same force. Yes, with the SAME FORCE, however F=m*a, so the great difference in mass makes Nina's acceleration much bigger than the Earth's one.

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A Martian leaves Mars in a spaceship that is heading to Venus. On the way, the spaceship passes earth with a speed v = 0.80c rel

hjlf

To find the relative distance from one point to another it is necessary to apply the Relativity equations.

Under the concept of relativity the distance measured from a spatial object is given by the equation

$l = l_0 \sqrt{1-\frac{v^2}{c^2}}$

Where

$l_0$ = Relative length

v = Velocity of the spaceship

c = Speed of light

Replacing with our values we have that

$l = l_0 \sqrt{1-\frac{v^2}{c^2}}$

$l = 1.2*10^{11} \sqrt{1-\frac{0.8c^2}{c^2}}$

$l = 1.2*10^{11} \sqrt{1-0.8^2}$

$l = 7.2*10^{10}m$

Therefore the distance between Mars and Venus measured by the Martin is $7.2*10^{10}m$

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3 years ago

Can anyone tell me the answer to this problem:)

Mrrafil [7]

The answer is B, lithium would become positive and bromium would become negative.

6 0

4 years ago

Planets A and B have the same size, mass, and direction of travel, but planet A is traveling through space at half the speed of

Ganezh [65]

Answer:

B. You would weigh the same on both planets because their masses and the distance to their centers of gravity are the same.

Explanation:

Given that Planets A and B have the same size, mass.

Let the masses of the planets A and B are $m_A$ and $m_B$ respectively.

As masses are equal, so $m_A=m_B\cdots(i)$ .

Similarly, let the radii of the planets A and B are $r_A$ and $r_B$ respectively.

As radii are equal, so $r_A=r_B\cdots(ii)$ .

Let my mass is m.

As the weight of any object on the planet is equal to the gravitational force exerted by the planet on the object.

So, my weight on planet A, $w_A= \frac {Gm_Am}{r_A^2}$

my weight of planet B, $w_B=\frac {Gm_Bm}{r_B^2}$

By using equations (i) and (ii),

$w_B=\frac {Gm_Am}{r_A^2}=w_A$ .

So, the weight on both planets is the same because their masses and the distance to their centers of gravity are the same.

Hence, option (B) is correct.

4 0

3 years ago

A point charge +Q is located on the x axis at x = a, and a second point charge –Q is located on the x axis at x = –a. A Gaussian

Anna [14]

Answer:

Net flux through the surface is zero.

Explanation:

Recall that the net electric flux through a closed surface depends on the net charge enclosed inside that surface.

In our case, there are two point charges of exactly opposite charge (net charge - zero), which are located inside the Gaussian surface of radius "2 a" centered at the origin - both charges are located at a distance "a" from the origin of coordinates, therefore inside the Gaussian surface.

Then the net flux through the surface is also ZERO.

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4 years ago

A rock with a mass of 10.0kg falls 25.0m to

Jlenok [28]

Answer:

man brainly should put a rank for having negative points

Explanation:

that would be me right now

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3 years ago