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aliya0001 [1]
4 years ago
12

When Nina jumps into the air, the Earth pulls her back down through the force of gravity. What else occurs?

Physics
2 answers:
Alex Ar [27]4 years ago
5 0
It is A. hope this helps
Nookie1986 [14]4 years ago
5 0
1) WRONG. Since gravitational force is an attractive force.
2) WRONG. The Earth does accelerate but the acceleration is so small that it's negligible. However it DOES ACCELERATE.
3) CORRECT.
4) WRONG. Mass means gravitational field, so Nina might be small compared to the Earth but it still creates a gravitational field around her. This answer is also wrong because it's breaking Newton's third law of action-reaction. If Earth pulls Nina, then Nina pulls the Earth back with the same force. Yes, with the SAME FORCE, however F=m*a, so the great difference in mass makes Nina's acceleration much bigger than the Earth's one.
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To find the relative distance from one point to another it is necessary to apply the Relativity equations.

Under the concept of relativity the distance measured from a spatial object is given by the equation

l = l_0 \sqrt{1-\frac{v^2}{c^2}}

Where

l_0= Relative length

v = Velocity of the spaceship

c = Speed of light

Replacing with our values we have that

l = l_0 \sqrt{1-\frac{v^2}{c^2}}

l = 1.2*10^{11} \sqrt{1-\frac{0.8c^2}{c^2}}

l = 1.2*10^{11} \sqrt{1-0.8^2}

l = 7.2*10^{10}m

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3 years ago
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Mrrafil [7]
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Planets A and B have the same size, mass, and direction of travel, but planet A is traveling through space at half the speed of
Ganezh [65]

Answer:

B. You would weigh the same on both planets because their masses and the distance to their centers of gravity are the same.

Explanation:

Given that Planets A and B have the same size, mass.

Let the masses of the planets A and B are m_A and m_B respectively.

As masses are equal, so m_A=m_B\cdots(i).

Similarly, let the radii of the planets A and B are r_A and r_B respectively.

As radii are equal, so r_A=r_B\cdots(ii).

Let my mass is m.

As the weight of any object on the planet is equal to the gravitational force exerted by the planet on the object.

So, my weight on planet A, w_A= \frac {Gm_Am}{r_A^2}

my weight of planet B, w_B=\frac {Gm_Bm}{r_B^2}

By using equations (i) and (ii),

w_B=\frac {Gm_Am}{r_A^2}=w_A.

So, the weight on both planets is the same because their masses and the distance to their centers of gravity are the same.

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3 years ago
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Answer:

Net flux through the surface is zero.

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In our case, there are two point charges of exactly opposite charge (net charge - zero), which are located inside the Gaussian surface of radius "2 a" centered at the origin - both charges are located at a distance "a" from the origin of coordinates, therefore inside the Gaussian surface.

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