Answer:
(3S)-2-chloro-2,3-dimethylpentane is produced exclusively.
Explanation:
Electrophilic addition to (3S)-2,3-dimethylpent-1-ene proceeds through a carbocationic intermediate.
In the first step,
adds onto double bond to produce more stable tertiary carbocation. (protonation)
In the second step,
adds onto carbocation to produce (3S)-2-chloro-2,3-dimethylpentane exclusively.(nucleophilic addition)
So, option (d) is correct.
Answer:Calculate The PH Of The Solution After The Addition Of The Following Amounts Of HCl. PLEASE HELP! SHOW ALL STEPS!! This problem has been solved!
Explanation:
Answer:
0.203 is the mean of the concentration of the HCl solution
Explanation:
You have 5 concentrations. The most appropiate result is the mean of those results. The mean is a statistical defined as the sum of each result divided by the total amount of results. For the results of the problem, the mean is:
0.210 + 0.204 + 0.201 + 0.202 + 0.197 = 1.014 / 5 =
<h3>0.203 is the mean of the concentration of the HCl solution</h3>
Answer:
375 mL
Explanation:
M1*V1 = M2*V2
M1 = 1.00 M
V1 = ?
M2 = 0.750 M
V2 = 0.500 L
1.00 M * V1 = 0.750 M * 0.500 L
V1 = 0.750*0.500/1.00 = 0.375 L = 375 mL