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klio [65]
2 years ago
10

The nonvolatile, nonelectrolyte cholesterol, C27H46O (386.60 g/mol), is soluble in benzene C6H6. Calculate the osmotic pressure

generated when 14.6 grams of cholesterol are dissolved in 263 ml of a benzene solution at 298 K. The molarity of the solution is M. The osmotic pressure of the solution is atmospheres.

Chemistry
1 answer:
soldier1979 [14.2K]2 years ago
7 0

Answer:

Explanation:the formula for osmotic pressure is given in the first line, all the terms are explained before solution, from the question,

Molar mass=Mm=386.6

Mass= m= 14.6

Volume= 263/1000 = 0.263dm^3

Temperature=T= 298K.

Gas constant .R= 0.082

Then substitute into the equation πV= nRT

Making π subject of formula

π= nRT/V

Then further substitution

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Answer:

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Explanation:

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First of all we divide each by the molar mass of the element

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We divide each by the lowest value, in this case 0.662

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3 years ago
Part A
Elden [556K]

Answer:

ΔG° = -5.4 kJ/mol

ΔG = 873.2 J/mol = 0.873 kJ /mol

Explanation:

Step 1: Data given

ΔG (NO2) = 51.84 kJ/mol

ΔG (N2O4)  = 98.28 kJ/mol

Step 2:

ΔG = ΔG° + RT ln Q

⇒with Q = the reaction quatient

⇒with T = the temperature = 298 K

⇒with R = 8.314 J / mol*K

⇒with ΔG° = ΔG° (N2O4) - 2*ΔG°(NO2 )

⇒ ΔG° = 98.28 kJ/mol - 2* 51.84  kJ/mol

⇒ ΔG° = -5.4 kJ/mol

Part B

ΔG =  ΔG° =RT ln Q

⇒with G° = -5.4 kj/mol = -5400 j/mol

⇒ with R = 8.314 J/K*mol

⇒with T = 298 K

⇒with Q = p(N2O4)/ [ p(NO2) ]² = 1.63/0.36² = 12.577

ΔG = -5400 + 8.314 * 298 * ln(12.577)

ΔG = -5400 + 8.314 * 298 * 2.532

ΔG = 873.2 J/mol = 0.873 kJ/mol

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3 years ago
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