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rodikova [14]
2 years ago
8

1. What causes frost to form on the outside of acold container.​

Chemistry
1 answer:
Kamila [148]2 years ago
6 0

Answer:

condensation

Explanation:

Frost forms when an outside surface cools past the dew point. The dew point is the point where the air gets so cold, the water vapor in the atmosphere turns into liquid. This liquid freezes. If it gets cold enough, little bits of ice, or frost, form

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Explain a mixture of molecules
skad [1K]

Answer:

A mixture of molecules is a group of molecules in which there are multiple different elements and atoms, that are in either fixed proportions or random. There are heterogeneous and homogenous mixtures.

Explanation:

7 0
2 years ago
What is the volume of 0.640 grams of Oz gas at Standard Temperature and Pressure (STP)?
Ilia_Sergeevich [38]

Answer: The volume of 0.640 grams of O_{2} gas at Standard Temperature and Pressure (STP) is 0.449 L.

Explanation:

Given: Mass of O_{2} gas = 0.640 g

Pressure = 1.0 atm

Temperature = 273 K

As number of moles is the mass of substance divided by its molar mass.

So, moles of O_{2} (molar mass = 32.0 g/mol) is as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{0.640 g}{32.0 g/mol}\\= 0.02 mol

Now, ideal gas equation is used to calculate the volume as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\1.0 atm \times V = 0.02 mol \times 0.0821 L atm/mol K \times 273 K\\V = 0.449 L

Thus, we can conclude that the volume of 0.640 grams of O_{2} gas at Standard Temperature and Pressure (STP) is 0.449 L.

6 0
3 years ago
At a pressure of 782.3 mm Hg and 34.4 °C, a certain gas has a volume of 362.4 mL. What will
german

Answer: v2=331.289mL

Explanation:

Formula for ideal gas law is p1v1/T1=p2v2/T2

P1=782.3mmHg

P2=769mmHg at STP

V1=362.4mL

V2=?

T1=273+34.4=307.4k

T2=273k at STP

Then apply the formula and make v2 the subject of formula

V2= 782.3×362.4×273/760×307.4

V2=77397006.96/233624

V2=331.289mL

7 0
3 years ago
Identify what kind of ligand (weak or strong), what kind of wavelength (long or short), what kind of spin (high spin or low spin
anzhelika [568]

To find - Identify what kind of ligand (weak or strong), what kind

              of wavelength (long or short), what kind of spin (high spin or

              low spin) and whether it is paramagnetic or diamagnetic for

              the following complexes.

              1. [Mn(CN)6]4-

              2. [Fe(OH)(H2O)5]2

              3. [CrCl4Br2]3-

Step - by - Step Explanation -

1.

[Mn(CN)⁶]⁴⁻ :

Ligand - Strong

Wavelength - Short

Spin - Low spin

Number of unpaired electrons = 1 ∴ paramagnetic.

2.

[Fe(OH)(H₂O)₅]²⁺ :

Ligand - Weak ( both OH⁻ and H₂O )

Wavelength - Long

Spin - High spin

Number of unpaired electrons = 5 ∴ paramagnetic.

3.

[CrCl₄Br₂]³⁻ :

Ligand - Weak ( both Br⁻ and Cl⁻ )

Wavelength - Long

Spin - High spin

Number of unpaired electrons = 3 ∴ paramagnetic.

7 0
2 years ago
What is the sign of the charge of an electron
oksian1 [2.3K]

Answer:

Electrons have negative charge.

4 0
3 years ago
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