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vichka [17]
3 years ago
6

How is thermal energy naturally transferred between objects?

Physics
1 answer:
Sladkaya [172]3 years ago
5 0

The second law of thermodynamics establishes restrictions on the flow of thermal energy between two bodies. This law states that the energy does not flow spontaneously from a low temperature object T1, to another object that is at a high temperature T2.

For example. Suppose you place your cell phone on the table. Your phone is at a temperature of 40 ° C and the table is at 19 ° C. Then, it is impossible for the table to spontaneously transfer its thermal energy to the telephone, and so that the table gets colder and the telephone warmer.


Finally we can say that the correct option is B: From the hotter object to the cooler object

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LenaWriter [7]

Answer:

The low points are called troughs

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A normal blood pressure reading is less than 120/80 where both numbers are gauge pressures measured in millimeters of mercury (m
KIM [24]

The pressure value is given by the equation,

P= \rho gh

Where,

\rho represents the density of the liquid

g= gravity

h= Heigth

A) For the measurement of the guage pressure we have the data data,

\rho_{mercury} = 13.6*10^3kg/m^3

h=0.0930m

g=9.8m/s^2

Replacing we get,

P_g=\rho_{mercury}gh

[tex]P_g = (13.6*10^3)(9.8)(0.0930)P_g = 12395Pa[/tex]

In order to find the Absolute pressure, we perform a sum between the atmospheric pressure and that of the Gauge,

B) The atmospheric pressure at sea level is 101325Pa, assuming ideal conditions, we will take this pressure for our calculation, so

P_T = P_a+P_g\\P_T = 101325Pa+12395Pa\\P_T = 113720Pa\\P_T = 113.7kPa

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3 years ago
What’s the net force of an object being throwing into the air
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Five liters of air at 50 c is warmed to 100c what is the new volume if the pressure remain constant
KonstantinChe [14]
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\frac{T_1}{V_1}= \frac{T_2}{V_2} (1)
where 1 and 2 label the initial and final conditions of the gas.

Before applying the law, we must convert the temperatures in Kelvin:
T_1 = 50^{\circ}C + 273 = 323 K
T_2 = 100^{\circ}C+273=373 K
The initial volume of the gas is V_1 = 5 L, so if we re-arrange (1) we find the new volume of the gas:
V_2 = V_1  \frac{T_2}{T_1}=(5 L) \frac{373 K}{323 K}=5.77 L
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harina [27]

Answer:

Less than 36kilo's

Explanation:

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