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andrezito [222]
2 years ago
15

Is anyone good with 9-10th grade physics?? Please pm me I have a few questions.

Physics
1 answer:
Tcecarenko [31]2 years ago
3 0
Let's give it a whirl ..... 
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A mass oscillates up and down on a vertical spring with an amplitude of 3 cm and a period of 2 s. What total distance does the m
harina [27]

Explanation:

It is given that,

A mass oscillates up and down on a vertical spring with an amplitude of 3 cm and a period of 2 s. It is a case of simple harmonic motion. If the amplitude of a wave is T seconds, then the distance cover by that object is 4 times the amplitude.

In 2 seconds, distance covered by the mass is 12 cm.

In 1 seconds, distance covered by the mass is 6 cm

So, in 16 seconds, distance covered by the mass is 96 cm

So, the distance covered by the mass in 16 seconds is 96 cm. Hence, this is the required solution.

6 0
3 years ago
Okay! Last question was a warm-up question. And now to get your brain thinking some more, how about another one?:
den301095 [7]
The correct answer is a fishhook
5 0
2 years ago
When exposed to a radioactive source which emits 1.2-MeV gamma-rays, a particular material is found to have a half-value thickne
iren2701 [21]

Answer:E

Explanation:

It is given that Energy of gamma ray is E=1.2 Mev

Shielding effect can be measured by measuring the fraction of gamma rays blocked by shield. If certain thickness will able to block half the radiation then to block 75% radiation we need to add same amount of thickness in order to block the remaining radiation.

i.e. \frac{E}{2} fraction is blocked by 10 cm thickness

then remaining radiation is \frac{E}{2}

another 10 cm thickness will block the remaining half radiation i.e. \frac{1}{2}\times \frac{E}{2}=\frac{E}{4}

so total 75 % radiation will be blocked

4 0
2 years ago
The sound source of a ship’s sonar system operates at a frequency of 22.0 kHz . The speed of sound in water (assumed to be at a
Degger [83]

Answer:

147.456077993 Hz

Explanation:

f_0 = Frequency of the sonar = 22 kHz

v_w = Velocity of the whale = 4.95 m/s

v = Speed of sound in water = 1482 m/s

The difference in frequency is given by

\Delta f=f_0\times\dfrac{2v_{w}}{v-v_w}\\\Rightarrow \Delta f=22000\times\dfrac{2\times 4.95}{1482-4.95}\\\Rightarrow \Delta f=147.456077993\ Hz

The difference in frequency is 147.456077993 Hz

6 0
2 years ago
QUESTION 36
mel-nik [20]

Answer:

Explanation:

m = ρV = 1.03( 1000 kg/m³)(π(2² m²)(3.0 m)) = 12360π kg

m ≈ 38,830 kg

5 0
3 years ago
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