Answer:
D) Some of the light passes through, and some of the light is absorbed or scattered by the object.
Explanation:
When light strikes translucent materials, only some of the light passes through them. The light does not pass directly through the materials. ... When light strikes an opaque object none of it passes through. Most of the light is either reflected by the object or absorbed and converted to heat.
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Answer:
yes
Explanation:
The plants use water (H2O) from the soil and carbon dioxide (CO2) from the air and recombine them to form carbohydrates (CH2O) and oxygen (O2).
Answer:
1. Speed and velocity both involve a numeric rate describing the distance traveled by a body in a unit of time. However, speed describes the rate of a body traveling in any direction in a unit of time, while velocity describes the rate of a body traveling in a particular direction in a unit of time.
2. Answers may vary, but should resemble the following:
Average velocity explains the velocity the body traveled overall, not taking into consideration each spot in the trip. If a car moves at 65 km/h on average, it may have slowed down for some parts and sped up for others. Overall though, it would have made a certain distance of travel within a specified unit of time that totals the average velocity of 65 km/h.
Instantaneous velocity explains the velocity of a body at a particular instant of the trip. The instantaneous velocity of a car stopped at a stop sign would be 0 m/s even if it was moving before and will continue to move after this stop. The velocity at that particular instant is the instantaneous velocity.
Uniform velocity is when the distance being covered is changing uniformly with time. For example, if a car moves 20 km every 30 minutes and continues to do so in the same direction, it's traveling with a uniform velocity.
3. a=v2−v1t
a=20 m/s−60 m/s6 s
a=−406
a = –6.7 m/s2
4. v2 = v1 + at
v2 = 14 m/s + (3 m/s2 × 6 s)
v2 = 14 + 18
v2 = 32 m/s
5. v=st
v=375 km5 h
v = 75 km/h
6. First, convert the minutes to seconds. Since there are 60 seconds in one minute, multiply:
60 × 15 (minutes) = 900 seconds
s = v × t
s = 6 m/s × 900 s
s = 5,400 m
7. t=sv
t=80 km35 km/hr
t = 2.29 hr
8. a=v2−v1t
a=50 m/s−15 m/s4 s
a=35 m/s4 s
a = 8.75 m/s2
9. vav=v1+v22
vav=15 m/s+50 m/s2
vav=65 m/s2
vav = 32.5 m/s
10. a=v2−v1t
a=0 m/s−11.5 m/s3.5 s
a = –3.29 m/s2
Explanation:
Answer:
v_oy = 16.33 m/s
Explanation:
To find the vertical velocity of the tiger, you use the information about the horizontal velocity and maximum horizontal distance traveled.
You use the following formula for the range of the trajectory:
( 1 )
v_ox: horizontal initial velocity = 4.5m/s
v_oy: vertical initial velocity = ?
g: gravitational acceleration = 9.8m/s^2
x_max: range of the trajectory = 15 m
You do v_oy the subject of the formula ( 1 ) and you replace the values of the other parameters in order to calculate v_oy:
hence, the initial vertical velocity of the tiger is 16.33m/s
