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2 years ago

The clean water act___

Physics

1 answer:

Kitty [74]2 years ago

5 0

My answer is the clean water act OF 1972

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What happens when two minerals have different arrangements of Atoms

zaharov [31]

The overall arrangements of the atoms produce crystals

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2 years ago

A magnetic B field of strength 0.9 T is perpendicular to a loop with an area of 3 m2. If the area of the loop is reduced to zero

Alexeev081 [22]

Answer:

The magnitude of induced emf is 5.4 V

Explanation:

Given:

Magnetic field $B = 0.9$ T

Area of loop $\Delta A = 3$ $m^{2}$

Time take to reduce loop to zero $\Delta t = 0.5$ sec

To find induced emf we use faraday's law,

Induced emf is given by,

$\epsilon = -\frac{\Delta \phi}{\Delta t}$

Here minus sign shows lenz law, for finding magnitude of emf we ignore it.

Where $\phi = B\Delta A$

Put the value of flux and find induced emf,

$\epsilon = \frac{B\Delta A}{\Delta t}$

$\epsilon = \frac{0.9 \times 3}{0.5}$

$\epsilon = 5.4$ V

Therefore, the magnitude of induced emf is 5.4 V

3 0

3 years ago

A 5.0-ohm resistor, a 10.0-ohm resistor, and a 15.0-ohm resistor are connected in parallel with a battery. The current through t

Kaylis [27]

Answer:

E = 3456 J

Explanation:

The electrical energy expended in a resistor can be easily calculated by using the following formula:

$E = Pt$

where,

E = Energy Expended = ?

I = current through 5 ohm resistor = 2.4 A

R = Resistance = 5 ohms

P = Electrical Power = VI

Since,

V = IR (Ohm's Law)

Therefore,

P = (IR)(I) = I²R = (2.4 A)²(5 ohms) = 28.8 Watt

t = time taken = (2 min)(60 s/1 min) = 120 s

Therefore,

E = (28.8 Watt)(120 s)

8 0

3 years ago

A 41-turn square coil of area 0.074 m2 and a 123-turn circular coil are both placed perpendicular to the same changing magnetic

vesna_86 [32]

Answer:

<h3>The area of second coil is ≅ 0.025 $m^{2}$ </h3>

Explanation:

Given :

No. of turns in the first coil $N_{1} = 41$

No. of turns in the second coil $N_{2} = 123$

Area of first coil $A_{1} = 0.074 m^{2}$

According to the law of electromagnetic induction,

Induced emf = $-N \frac{d \phi}{dt}$

Where $\phi =$ magnetic flux.

Since given in question emf of both coil is same so we compare above equation.

$-\frac{N_{1} d\phi _{1} }{dt_{1} } = -\frac{N_{2} d\phi _{2} }{dt_{2} }$

$\frac{N_{1} A_{1} dB_{1} }{dt_{1} } = \frac{N_{2} A_{2} dB_{2} }{dt_{2} }$

$A_{2} = \frac{N_{1} A_{1} }{N _{2} }$

$A_{2} = \frac{41 \times 0.074 }{123 }$

$A_{2} = 0.0246 = 0.025 m^{2}$

Therefore, the area of second coil is ≅ 0.025 $m^{2}$

4 0

3 years ago

Rope BCA passes through a pulley at point C and supports a crate at point A. Rope segment CD supports the pulley and is attached

RUDIKE [14]

Answer:

Wmax = 63.65 ≈ 64 lb

Explanation:

6 0

2 years ago