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What is the kinetic energy of a 620.0 kg roller coaster moving with a velocity of 9.00 m/s?

Darina [25.2K]

The kinetic energy of a moving object is calculated through the equation,
KE = 0.5mv²
where m is the mass and v is the velocity.
Substituting the known values,
KE = 0.5(620 kg)(9 m/s)²
KE = 25,110 J
Thus, the kinetic energy is equal to 25,110 J.

3 0

3 years ago

Read 2 more answers

Nancy rides her bike with a constant

Sloan [31]

Answer:

2 and a half hours

Explanation:

Nancy rides her bike at 10 miles per hour. After the first hour, she would have ridden 10 miles. After the second hour, she would hvae ridden 20 miles. She needs to ride 5 more miles, which is half of her 10 miles that she rides every hour. Since it is half of her speed of miles per hour, it will take her another half an hour to ride the 5 miles. Added together, Nancy takes 2 and a half hours.

7 0

3 years ago

Two trains are blowing their whistles. The first train is stationary, and the

Liono4ka [1.6K]

Answer:

A I think

Pls Mark Brainiest, I'm trying to become Virtuoso

3 0

3 years ago

A student drops two metallic objects into a 120-g steel container holding 150 g of water at 25°C. One object is a 206-g cube of

spayn [35]

Answer:

Mass of the aluminium chunk = 278.51 g

Explanation:

For an isolated system as given the energy lost and gains in the system will be zero therefore sum of all transfer of energy will be zero,as the temperature will also remain same

A specific heat formula is given as

Energy Change = Mass of liquid x Specific Heat Capacity x Change in temperature

Q = m×c×ΔT

Heat gain by aluminium + heat lost by copper = 0 (1)

For Aluminium:

Q = $m\times0.897\frac{J}{g.k}\times(25-5)$

Q = m x 17.94 joule

For Copper:

$Q= 206g\times0.385\frac{J}{g.k} \times(88-25)$

Q= 4996.53 Joule

from eq 1

m x 17.94 = 4996.53

$mass of aluminium = \frac{4996.53}{17.94} g$

Mass of the aluminium chunk = 278.51 g

3 0

3 years ago

When two resistors are wired in series with a 12 V battery, the current through the battery is 0.33 A. When they are wired in pa

MA_775_DIABLO [31]

Answer:

If R₂=25.78 ohm, then R₁=10.58 ohm

If R₂=10.57 then R₁=25.79 ohm

Explanation:

R₁ = Resistance of first resistor

R₂ = Resistance of second resistor

V = Voltage of battery = 12 V

I = Current = 0.33 A (series)

I = Current = 1.6 A (parallel)

In series

$\text{Equivalent resistance}=R_{eq}=R_1+R_2\\\text {From Ohm's law}\\V=IR_{eq}\\\Rightarrow R_{eq}=\frac{12}{0.33}\\\Rightarrow R_1+R_2=36.36\\ Also\ R_1=36.36-R_2$

In parallel

$\text{Equivalent resistance}=\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\\\Rightarrow {R_{eq}=\frac{R_1R_2}{R_1+R_2}$

$\text {From Ohm's law}\\V=IR_{eq}\\\Rightarrow R_{eq}=\frac{12}{1.6}\\\Rightarrow \frac{R_1R_2}{R_1+R_2}=7.5\\\Rightarrow \frac{R_1R_2}{36.36}=7.5\\\Rightarrow R_1R_2=272.72\\\Rightarrow(36.36-R_2)R_2=272.72\\\Rightarrow R_2^2-36.36R_2+272.72=0$

Solving the above quadratic equation

$\Rightarrow R_2=\frac{36.36\pm \sqrt{36.36^2-4\times 272.72}}{2}$

$\Rightarrow R_2=25.78\ or\ 10.57\\ If\ R_2=25.78\ then\ R_1=36.36-25.78=10.58\ \Omega\\ If\ R_2=10.57\ then\ R_1=36.36-10.57=25.79\Omega$

∴ If R₂=25.78 ohm, then R₁=10.58 ohm

If R₂=10.57 then R₁=25.79 ohm

6 0

3 years ago

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