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mylen [45]
2 years ago
13

The rubber ducky has a mass of 5 grams and a volume of 75 mL. How much water does he displace?

Physics
1 answer:
xeze [42]2 years ago
7 0

Answer:

Volume displaced by ducky = 75 mL = 7.5 x 10⁻⁵ m³

Mass displaced by the ducky = 7.5 x 10⁻² kg = 75 grams

Explanation:

The ducky will displace the volume of the water equal to its own volume.

<u>Volume displaced by ducky = 75 mL = 7.5 x 10⁻⁵ m³</u>

And the mass displaced by ducky will be equal to:

Mass displaced by the ducky = (Density of Water)(Volume displaced by ducky)

Mass displaced by the ducky = (1000 kg/m³)(7.5 x 10⁻⁵ m³)

<u>Mass displaced by the ducky = 7.5 x 10⁻² kg = 75 grams</u>

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Vector A has y-component Ay= +15.0 m . A makes an angle of 32.0 counterclockwise from the +y-axis. What is the x component of A?
Gemiola [76]

Answer:

x-component=-9.3 m

Magnitude of A=17.7m

Explanation:

We are given that

A_y=+15 m

\theta=32^{\circ}

We have to find the x-component of A and magnitude of A.

According to question

A_y=\mid A\mid cos\theta

Substitute the values then we get

15=\mid A\mid cos32

\mid A\mid =\frac{15}{cos32}=\frac{15}{0.848}

\mid A\mid=17.7m

tan\theta=\frac{perpendicular\;side}{Base}

tan32=\frac{A_x}{A_y}=\frac{A_x}{15}

0.62\times 15=A_x

A_x=9.3

The value of x-component of A is negative because the vector A lie  in second quadrant.

Hence, the x- component of A=-9.3 m

6 0
3 years ago
Read 2 more answers
What distance will a car traveling at a speed of 15 m/s cover in 300 s?
AnnZ [28]

Distance formula: d = st

d = 15 * 300

d = 4,500m

Best of Luck!

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3 years ago
A spacecraft left Earth to collect soil samples from Mars. Which statement is true about the strength of Earth’s gravity on the
ryzh [129]

Answer:

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3 years ago
A mine elevator is supported by a single steel cable 0.0125 m in diameter. The total mass of the elevator cage and occupants is
Sonja [21]

Answer:

0.8895m

Explanation:

Cable diameter = 0.0125m

Mass of elevator = 6450kg

Young Modulus(E) = 2.11*10¹¹N/m

∇l (change in length) =

L = 362m

A = Πr², but r = d / 2 = 0.0125 / 2 = 0.00625m

A = 3.142 * (0.00625)² = 1.227*10^-4m²

Young Modulus (E) = Tensile stress / Tensile strain

E = (F / A) / ∇l / L

F = mg = 6450 * 9.8 = 63210N

2.11*10¹¹ = (63210 / 1.22*10^-4) / (∇l / 362)

2.11*10¹¹ = 5.18*10⁸ / (∇l / 362)

2.11*10¹¹ = (5.18*10⁸ * 362) / ∇l

2.11*10¹¹ = 1.875*10¹¹ / ∇l

∇l = 1.875*10¹¹ / 2.11*10¹¹

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Which situation describes a system with decreasing gravitational potential energy?
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Answer: a boy jumping down

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