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3 years ago

The rubber ducky has a mass of 5 grams and a volume of 75 mL. How much water does he displace?

Physics

1 answer:

xeze [42]3 years ago

7 0

Answer:

Volume displaced by ducky = 75 mL = 7.5 x 10⁻⁵ m³

Mass displaced by the ducky = 7.5 x 10⁻² kg = 75 grams

Explanation:

The ducky will displace the volume of the water equal to its own volume.

Volume displaced by ducky = 75 mL = 7.5 x 10⁻⁵ m³

And the mass displaced by ducky will be equal to:

Mass displaced by the ducky = (Density of Water)(Volume displaced by ducky)

Mass displaced by the ducky = (1000 kg/m³)(7.5 x 10⁻⁵ m³)

Mass displaced by the ducky = 7.5 x 10⁻² kg = 75 grams

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awhite billiard ball with mass mw = 1.47 kg is moving directly to the right with a speed of v = 3.01 m/s and collides elasticall

pochemuha

Answer:

speed of white ball is 1.13 m/s and speed of black ball is 2.78 m/s

initial kinetic energy = final kinetic energy

$KE = 6.66 J$

Explanation:

Since there is no external force on the system of two balls so here total momentum of two balls initially must be equal to the total momentum of two balls after collision

So we will have

momentum conservation along x direction

$m_1v_{1i} + m_2v_{2i} = m_1v_{1x} + m_2v_{2x}$

now plug in all values in it

$1.47 \times 3.01 + 0 = 1.47 v_1cos68 + 1.47 v_2cos22$

so we have

$3.01 = 0.375v_1 + 0.927v_2$

similarly in Y direction we have

$m_1v_{1i} + m_2v_{2i} = m_1v_{1y} + m_2v_{2y}$

now plug in all values in it

$0 + 0 = 1.47 v_1sin68 - 1.47 v_2sin22$

so we have

$0 = 0.927v_1 - 0.375v_2$

$v_2 = 2.47 v_1$

now from 1st equation we have

$3.01 = 0.375 v_1 + 0.927(2.47 v_1)$

$v_1 = 1.13 m/s$

$v_2 = 2.78 m/s$

so speed of white ball is 1.13 m/s and speed of black ball is 2.78 m/s

Also we know that since this is an elastic collision so here kinetic energy is always conserved to

initial kinetic energy = final kinetic energy

$KE = \frac{1}{2}(1.47)(3.01^2)$

$KE = 6.66 J$

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