We know from Newtons law of force that
Work done = Force * Distance moved
We know from the question that
Force applied = 70 Newton
Distance moved = 9 meters.
Since the object is moving in the same direction as the force applied
So
Work done = Force * Distance moved
= 70 * 9 newton meters(Nm)
= 630 newton meters(Nm)
= 630 joules
Answer:
The mass of the ball is 0.23 kg
Explanation:
Given that
radius ,r= 3.74 cm
Density of the milk ,ρ = 1.04 g/cm³ = 1.04 x 10⁻³ kg/cm³
Normal force ,N= 9.03 x 10⁻² N
The volume of the ball V
V= 219.13 cm³
The bouncy force on the ball = Fb
Fb = ρ V g
Fb + N = m g
m=Mass of the ball = Density x volume
m = γ V , γ =Density of the Ball
ρ V g + N = γ V g ( take g= 10 m/s²)
γ = 0.00108 kg/cm³
m = γ V
m = 0.00108 x 219.13
m= 0.23 kg
The mass of the ball is 0.23 kg
Y₀ = initial position of the balloon at the top of the building = 44 m
Y = final position of the balloon at halfway down the building = 44/2 = 22 m
a = acceleration of the balloon = - 9.8 m/s²
v₀ = initial velocity of the balloon = 0 m/s
v = final velocity of the balloon = ?
using the kinematics equation
v² = v₀² + 2 a (Y - Y₀)
inserting the values
v² = 0² + 2 (- 9.8) (22 - 44)
v = 20.78 m/s
Answer:
H = 8.45 m
Explanation:
Given that,
Angle of projection,
The initial velocity of the ball, u = 20 m/s
We need to find the maximum height reached by the ball. The formula for the maximum height is given by :
So, the maximum height reached by the ball is 8.45 m.