Which of these statements does not describe electricity?

Please help!

Afina-wow [57]

False.
False.
True.
If you need more explaination just let me know!

7 0

3 years ago

When do you use 6.02*10^23?? Do you use it when going to atoms or molecules????

Andrew [12]

You would use it in both atoms and molecules if it’s in are large quantity

3 0

3 years ago

Adding a(n) [Select]<br> ' will slow down a chemical reaction.

leva [86]

Inhibitor

Explanation:

Adding an inhibitor will slow down a chemical reaction. Inhibitors works like a negative catalyst.

The addition of a foreign body can influence the rate of a reaction.

When a foreign body slows down a reaction, it is called an inhibitor.
An inhibitor is a negative catalyst that will slow down a reaction.
Such substances do not allow a reaction to proceed freely and very fast.
They work in the opposite way a normal catalyst would.
It is good to know conditions and chemicals that can inhibit a chemical reaction.

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4 0

3 years ago

Pls help need this to pass

SOVA2 [1]

Bulk property are those properties that does not depend on the amount of substance.

<h3>What is a bulk property?</h3>

The term bulk property can also be referred to as the intensive properties of a substance. These are those properties that does not depend on the amount of substance. This means that they are characteristic of the material.

The percent by mass refers to the percentage of an atom that is present in a compound. If we must be able to calculate the percentage by mass then we must know the mass of the sample and the masses of the elements found in the sample.

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8 0

2 years ago

Read 2 more answers

Determine the molecular formula for each of the following compounds from the

bulgar [2K]

The molecular formula for each of the following compound given the data is

C₂H₆
C₂H₂
C₄H₈Cl₂

<h3>A. How to determine the molecular formula </h3>

We'll begin by calculating the empirical formula. This can be obtained as follow:

C = 80%
H = 20%
Empirical formula =?

Divide by their molar mass

C = 80 / 12 = 6.67

H = 20 / 1 = 20

Divide by the smallest

C = 6.67 / 6.67 = 1

H = 20 / 6.67 = 3

Thus, the empirical formula of the compound CH₃

Thus, the molecular formula of the compound can be obtained as follow

Empirical formula = CH₃
Molar mass of compound = 30 g/mol
Molecular formula =?

Molecular formula = empirical × n = mass number

[CH₃]n = 30

[12 + (3×1)]n = 30

15n = 30

Divide both side by 15

n = 30 / 15

n = 2

Molecular formula = [CH₃]n

Molecular formula = [CH₃]₂

Molecular formula = C₂H₆

Thus, the molecular formula of the compound is C₂H₆

<h3>B. How to determine the molecular formula </h3>

We'll begin by calculating the empirical formula. This can be obtained as follow:

C = 92.3%
H = 7.7%
Empirical formula =?

Divide by their molar mass

C = 92.3 / 12 = 7.7

H = 7.7 / 1 = 7.7

Divide by the smallest

C = 7.7 / 7.7 = 1

H = 7.7 / 7.7 = 1

Thus, the empirical formula of the compound CH

Thus, the molecular formula of the compound can be obtained as follow

Empirical formula = CH
Molar mass of compound = 26 g/mol
Molecular formula =?

Molecular formula = empirical × n = mass number

[CH]n = 26

[12 + 1]n = 26

13n = 26

Divide both side by 13

n = 26 / 13

n = 2

Molecular formula = [CH]n

Molecular formula = [CH]₂

Molecular formula = C₂H₂

Thus, the molecular formula of the compound is C₂H₂

<h3>C. How to determine the molecular formula </h3>

We'll begin by calculating the empirical formula. This can be obtained as follow:

C = 37.5%
H = 6.3%
Cl = 55.8%
Empirical formula =?

Divide by their molar mass

C = 37.5 / 12 = 3.125

H = 6.3 / 1 = 6.3

Cl = 55.8 / 35.5 = 1.572

Divide by the smallest

C = 3.125 / 1.572 = 2

H = 6.3 / 1.572 = 4

Cl = 1.572 / 1.572 = 1

Thus, the empirical formula of the compound C₂H₄Cl

Thus, the molecular formula of the compound can be obtained as follow

Empirical formula = C₂H₄Cl
Molar mass of compound = 127 g/mol
Molecular formula =?

Molecular formula = empirical × n = mass number

[C₂H₄Cl]n = 127

[(2×12) + (4×1) + 35.5]n = 127

63.5n = 127

Divide both side by 63.5

n = 127 / 63.5

n = 2

Molecular formula = [C₂H₄Cl]n

Molecular formula = [C₂H₄Cl]₂

Molecular formula = C₄H₈Cl₂

Thus, the molecular formula of the compound is C₄H₈Cl₂

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7 0

2 years ago