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Luden [163]
3 years ago
10

Which of these statements does not describe electricity?

Chemistry
1 answer:
Tanzania [10]3 years ago
5 0

Answer:

answer is B. Electricity cools down devices as it travels through them

Explanation

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What did thomson’s model of the atom called
nignag [31]

Answer:

Plum pudding model

Explanation:

Thomson’s model of the atom called: PLUM PUDDING MODEL

8 0
3 years ago
Read 2 more answers
Heres a list of Compounds and Molecules
kobusy [5.1K]

Answer:

ibgb ybhy

Explanation:

7 0
3 years ago
When the fish-tank water has a pH of 8.0, the hydronium ion concentration is 1.0 × 10-8 mole per liter. What is the hydronium io
Oduvanchick [21]
You must know and use the formula for pH.


pH = - log [H3O+], where [H3O+] is the molar concentration of hydronium ion.


So, when pH is 8.0 => 8.0 = - log [H3O+] and you can use antilogarithm (the inverse function of logarithm) to find [H3O+], in this way:


[H3O+] = 10^-8 = 1 * 10 ^-8 M


When, pH = 7.0 =>

7.0 = - log [H3O+] => [H3O+] = 1 * 10^ -7 M


Answer: 1*10^-7 mole / liter
5 0
3 years ago
HELP! Answer the question below PLEASE
garri49 [273]

Answer: Francesco Redis Experiment part 1 : The maggots were not observed in setup B and setup C because the jars were covered.

part 2 : He discovered that maggots appeared on the meat in the control jar, the jar left open. No maggots appeared in the jar covered with gauze.

Pasteur Experiment

part 1:In the pastures Experiment the microorganisms come from the air.

part 2:Louis Pasteur's pasteurization experiment illustrates the fact that the spoilage of liquid was caused by particles in the air rather than the air itself.

Explanation:

8 0
3 years ago
Find the ph of a 0.250 m solution of nac2h3o2. (the ka value of hc2h3o2 is 1.80×10−5). express your answer numerically to four s
Slav-nsk [51]
Answer is: pH value of solution of NaC₂H₃O₂ is 9.07.
Chemical reaction: C₂H₃O₂⁻ + H₂O ⇄ HC₂H₃O₂ + OH⁻.
Ka(HC₂H₃O₂) = 1,8·10⁻⁵.<span>
Ka · Kb = Kw.
</span>1,8·10⁻⁵ mol/dm³ · Kb = 1·10⁻¹⁴ mol²/dm⁶; the ionic product of water at 25°C.<span>
Kb(</span>C₂H₃O₂⁻) = 1·10⁻¹⁴ mol²/dm⁶ ÷ 1,8·10⁻⁵ mol/dm³.<span>
Kb(</span>C₂H₃O₂⁻) = 5,56·10⁻¹⁰ mol/dm³.
c(C₂H₃O₂⁻) = 0,25 M.
[OH⁻] = [HC₂H₃O₂] = x.
[C₂H₃O₂⁻] = 0,25 M - x.
Kb = [OH⁻] · [HC₂H₃O₂] / [C₂H₃O₂⁻].
5,56·10⁻¹⁰ = x² / (0,25 M -x).
Solve quadratic equation: x = [OH⁻] = 0,0000118 M.
pOH = -log[OH⁻] = -log(0,0000118M) = 4,93.
pH + pOH = 14.
pH = 14 - 4,93 = 9,07.
6 0
3 years ago
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