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andreev551 [17]
3 years ago
14

Ozone located in the troposphere is _____

Chemistry
1 answer:
Leokris [45]3 years ago
4 0

Answer:

its A

Explanation:

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What is the empirical mass of SO2?<br> Answer using four significant figures.
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The atomic mass is 64.07
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there is a total of seventeen constitutional isomers for the molecular formula c5h13n. draw the skeletal formula of all three co
MAXImum [283]
Amines are derivatives of Ammonia (NH₃) in which atleast one hydrogen atom is replaced by an alkyl group. Amines are further classifies as;

Primary Amines:
                          In primary amines the nitrogen atom is attached to two hydrogen atoms and one alkyl group.

Secondary Amines:
                             In secondary amines the nitrogen atom is attached to two alkyl groups and one hydrogen atom.

Tertiary Amines:
                         In tertiary amines the nitrogen atom is attached to three alkyl groups, hence it has no hydrogen atom.

Below are three isomers of tertiary amines with molecular formula C₅H₁₃N.

5 0
4 years ago
The solubility product of calcium fluoride (CaF2(s); fluorite) is 310-11 at 25C. Could a fluoride concentration of 1.0 mg L-1
Finger [1]

The given question is incomplete. The complete question is as follows.

The solubility product of calcium fluoride () is  at 25 degrees C. Will a fluoride concentration of 1.0 mg/L be soluble in a water containing 200 mg/L of calcium?

Explanation:

Reaction equation for the given chemical reaction is as follows.

       CaF_{2} \rightleftharpoons Ca^{2+} + 2F^{-}

Therefore, expression for K_{sp} will be as follows.

        K_{sp} = [Ca^{2+}][F^{-}]^{2}

                     =

Also, moles of  per liter = \frac{\text{mass of F^{-} per L}}{\text{molar mass of F}}[/tex]

                = \frac{1.0 \times 10^{-3}}{19.0}

               = 5.263 \times 10^{-5} mol

Hence,    [F^{-}] = \frac{\text{moles of F^{-}}{volume}

                       = \frac{5.263 \times 10^{-5}}{1}

                      =  M

Now, moles of  per L = \frac{\text{mass of Ca^{2+} per L}}{\text{molar mass of Ca}}[/tex]

            = \frac{200 \times 10^{-3}}{40.1}

           =  M

Also,   [Ca^{2+}] = \frac{moles of Ca^{2+}}{volume}

                      = \frac{4.988 \times 10^{-3}}{1}

                     =  M

Hence, ionic product =

                 = (4.988 \times 10^{-3}) \times (5.263 \times 10^{-5})^{2}

                = 1.38 \times 10^{-11}

As, the ionic product is less than the K_{sp}, this means that the fluoride will be soluble in water containing the calcium.

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Goryan [66]

The kinetic energy of particles depends on temperature. As temperature increases, the kinetic energy of particles increases.

Temperature is defined as a measure of the average kinetic energy of the molecules of a substance. The higher the temperature of a substance the greater its kinetic energy.

From the foregoing, when the temperature is increased from 400K to 500K, greater kinetic energy is imparted to the molecules of the substance hence they move faster according to the kinetic theory of matter.

Learn more: brainly.com/question/10079361

7 0
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