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ArbitrLikvidat [17]
2 years ago
15

Find the work done by a 75.0 kg person in climbing a 2.50 m flight of stairs at a constant speed.

Physics
1 answer:
Lubov Fominskaja [6]2 years ago
6 0

Answer:

<em>1,839.375 Joules</em>

Explanation:

Work is said to be done is the force applied to an object cause the object to move through a distance.

Workdone = Force * Distance

Workdone = mass * acceleration due to gravity * distance

Given

Mass = 75.0kg

acceleration due to gravity = 9.81m/s²

distance = 2.50m

Substitute the given parameters into the formula:

Workdone = 75.0*9.81*2.50

Workdone = 1,839.375Joules

<em>Hence the workdone is 1,839.375 Joules</em>

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8 0
1 year ago
A pulse of red light and a pulse of blue light enter a glass block normal to its surface at the same time. after passing through
pshichka [43]
I believe the red light would go faster than the blue.
7 0
3 years ago
Read 2 more answers
The average rate of disappearance of ozone in the reaction is
olasank [31]

Answer:

1.3 x 10^(-2) atm/s

Explanation:

It follows the stoichiometry. For every mole of O3 that disappears, 1.5 moles (that is, 3/2) of O2 appears:

1.5 * 0.009 atm/s = 0.0135 atm/sec; the answer is 1.3 x 10^(-2) atm/s

7 0
2 years ago
Suppose you hear a clap of thunder 14.4 s after seeing the associated lightning strike. The speed of light in air is 3.00 ✕ 108
Marina86 [1]

Answer

Given,

Time to hear the clap = 14.4 s

speed of the light = 3 x 10⁸ m/s

Speed of sound = 343 m/s

a) distance where lightning strike

    D = s x t

    D = 14.4 x 343

   D = 4939.2 m

b) No, we do not need to know the value of speed of light. Because we need to calculate the distance where we hear the sound. To calculate that we need to know the speed of sound.

5 0
3 years ago
Suppose you first walk 12.0 m in a direction 200 west of north and then 20.0 m in a direction 40.00 south of west. How far are y
Tpy6a [65]

Complete Question

The  complete question is shown on the first uploaded image

Answer:

the compass direction of the resultant displacement is  \theta  =4.7^o south of west

Explanation:

Generally using cosine we can obtain the resultant R as follows

     R^2  =  A^2  + B^2 -2ABcos(70)

=>   R  =  \sqrt{12^2  + 20^2  - 2(12 ) *  (20) cos  70}

=>    R  =  19.48 \  m

We can obtain the direction of the resultant by first  using sine rule to obtain angle C as follows

       \frac{A}{sin  C}  =  \frac{R}{sin70 }

=>    C=  sin ^{-1} [\frac{A *  (sin 70)}{R} ]

=>    C =  sin ^{-1} [\frac{20 *  (sin 70)}{19.48} ]

=>  C =  74.7 ^o

Then the direction is obtained as

       \theta  =  C  -  70

=>    \theta  = 74.7   -  70

=>     \theta  =4.7^o

Hence the compass direction of the resultant displacement is  \theta  =4.7^o south of west

7 0
2 years ago
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