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Mumz [18]
3 years ago
6

Two very small +3.00-μC charges are at the ends of a meter stick. Find the electric potential (relative to infinity) at the cent

er of the meter stick.
Physics
1 answer:
PtichkaEL [24]3 years ago
4 0

Answer:

The electric potential at the center of the meter stick is 54 KV.

Explanation:

Electric potential (V) is given as:

i.e V = \frac{kq}{r}

Where: k is the Coulomb constant, q is the charge and r is the distance.

Given: q = 3.0 μC = 3.0 x 10^{-6} C, r = 0.5 m

So that,

V = \frac{9*10^{9}*3.0*10^{-6}  }{0.5}

   = \frac{2.7*10^{4} }{0.5}

V = 54000

  = 54 000 volts

The electric potential at the center of the meter stick is 54 KV.

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