Answer:
Explanation:
The expression for the calculation of the enthalpy change of a process is shown below as:-
Where,
is the enthalpy change
m is the mass
C is the specific heat capacity
is the temperature change
Thus, given that:-
Mass of ammonium nitrate = 1.25 g
Specific heat = 4.18 J/g°C
So,
Negative sign signifies loss of heat.
Also, 1 J = 0.001 kJ
So,
No, I would not expect the lighter to work at 25 °F.
25 °F ≈ -4 °C
The boiling point of butane is -1 °C.
At -4 °C, the vapour pressure of butane is not great enough to push back against atmospheric pressure.
The lighter won't work.
1) C because potential energy is always at the top first and has to most energy to speed down more.
2)A because potential energy is always at the top first
3)B because kinetic energy is when it starts to drop; so the perfect word for that is moving.
A liquid takes 10.14 x 10^6 J of energy to boil 28.47 kg at 298 K. Using the Latent heats of vaporization of some of the substances:
Acetone: 538,900 
Ammonia: 1,371,000 
Propane: 356,000 
Methane: 480,600 
Ethanol: 841,000 
Calculating the latent heat of vaporization of the given substance:
Heat required = 
Mass of the substance boiled = 28.47 kg
Latent heat of vaporization =
So the substance boiled is propane.
The metal ions become positive ions and the non-metal atoms become negative ions. There is a strong electrostatic force of attraction between these oppositely charged ions called an ionic bond.