Answer : The molar mass of the solute would be low.
Explanation :
Formula used for depression in freezing point is:
where,
= change in freezing point
= freezing point of solution
= freezing point of water
i = Van't Hoff factor
= freezing point constant
m = molality
= mass of solute
= mass of solvent
= molar mass of solute
From the formula we conclude that, when the freezing point of the solution read incorrectly that is freezing point of the solution is lower than the true freezing point then this means that change in freezing point would be high and the molar mass of the solute would be low.
Hence, the molar mass of the solute would be low.
<span>chemicals reacting are written on the left, what is formed is written on the right after the = sign
eg Copper + oxygen = copper oxide.
Hope this helps , mark as brainliest and say thanks THANKS..</span>
Answer:
fx87tx97td97td7rdd86ts86rxt6x96rs86rs8yrs7rx6rx6rs6rsi6rsi6rsyfdfx87tx97td97td7rdd864s86rxt6x96rs86rs8yrs7rx6rx6rs6rs 44sx64sx6itxi6rx4sx6itxi6rx6irxi6rz6r44sx64sx6itxi6rx4sx6itxi6rx6irxi6rz6rz6r
Answer:
"2.48 mole" of H₂ are formed. A further explanation is provided below.
Explanation:
The given values are:
Mole of Al,
= 3.22 mole
Mole of HBr,
= 4.96 mole
Now,
(a)
The number of mole of H₂ are:
⇒ 
or,
⇒ 
⇒ 
⇒ 
(b)
The limiting reactant is:
= 
(c)
The excess reactant is:
= 
