Molar solubility is number of moles of the solute that can be dissolved per liter of solution before the solution becomes saturated.
The molar solubility of lead(ii) chloride with ksp value of 2.4 × 10e4 can be solve as:
Ksp = s2 = 2.4 × 10e4
s2 = 2.4 × 10e4
s = √(2.4 × 10e4)
s = 154.9 mol/L
Answer:
\text{0.30 cm}^{3} \times \left (\dfrac{10^{-2}\text{ m}}{\text{1 cm}}\right )^{3} = 3.0 \times 10^{-7} \text{ m}^{3}
Explanation:
0.030 cm³ × ? = x m³
You want to convert cubic centimetres to cubic metres, so you multiply the cubic centimetres by a conversion factor.
For example, you know that centi means "× 10⁻²", so
1 cm = 10⁻² m
If we divide each side by 1 cm, we get 1 = (10⁻² m/1 cm).
If we divide each side by 10⁻² m, we get (1 cm/10⁻² m) = 1.
So, we can use either (10⁻² m/1 cm) or (1 cm/10⁻² m) as a conversion factor, because each fraction equals one.
We choose the former because it has the desired units on top.
The "cm" is cubed, so we must cube the conversion factor.
The calculation becomes

Answer:

Explanation:
Force is equal to mass times acceleration.

By dividing both sides by m, we rearrange the formula for a (acceleration).

The force is 6.2 Newtons, but we can convert the units to make the problem easier later on.
- A Newton is equal to 1 kg*m/s², so 6.2 N is equal to 6.2 kg*m/s².
The mass is 2300 grams, but we need to convert it to kilograms.
- To convert grams to kilograms, divide by 1,000
- 2300 g/1000= 2.3 kg

Substitute the values into the formula.

Divide. Note that the kilograms or "kg" will cancel each other out (this is why we converted the units).


Round to the nearest tenth. The 9 in the hundredth place tells us to round up to 2.7

The acceleration is about <u>2.7 meters per second squared.</u>